oba*_*abs 5 sql sql-server inner-join max where
我有两个表,一个"主"是主列表的名称,第二个"方案"是主列表中每个名称的多个方案的列表.我希望我的INNER JOIN查询从"scenario"表中获取具有列状态的ID的主列表,但仅获取基于scenarioID的最新状态.这是我尝试的代码和具有所需输出的表
SELECT DISTINCT a.[user], a.ID, a.Name, b.status
from master a
INNER JOIN scenario b ON a.ID = b.ID
WHERE
b.scenarioID = (
SELECT max(scenarioID) FROM scenario c2 WHERE c2.ID=c.ID)
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主
ID user Name
425 John Skyline
426 John Violin
427 Joe Pura
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脚本
ID ScenarioID status
425 1 active
425 2 active
425 3 done
426 1 active
426 2 active
427 1 done
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期望的输出
ID user Name status
425 John Skyline done
426 John Violin active
427 Joe Pura done
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您可以通过CROSS APPLY查找每个值的最新值来执行此操作:
Select M.ID, M.[User], M.Name, X.Status
From [Master] M
Cross Apply
(
Select Top 1 S.Status
From Scenario S
Where S.ID = M.ID
Order By S.ScenarioID Desc
) X
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另一种方法是使用 a ROW_NUMBER() PARTITIONEDon theID和ORDEREDby ScenarioID DESC:
;With OrderedStatuses As
(
Select M.Id, M.[User], M.Name, S.Status,
Row_Number() Over (Partition By S.Id Order By S.ScenarioID Desc) RN
From [Master] M
Join Scenario S On S.Id = M.Id
)
Select Id, [User], Name, Status
From OrderedStatuses
Where RN = 1
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这是使用 CTE 的稍微不同的公式,我通常发现它比子查询更容易阅读(当然,您的情况可能会有所不同)。
declare @Master table
(
ID bigint,
[user] varchar(16),
Name varchar(16)
);
declare @Scenario table
(
ID bigint,
ScenarioID bigint,
[status] varchar(16)
);
insert @Master values
(425, 'John', 'Skyline'),
(426, 'John', 'Violin'),
(427, 'Joe', 'Pura');
insert @Scenario values
(425, 1, 'active'),
(425, 2, 'active'),
(425, 3, 'done'),
(426, 1, 'active'),
(426, 2, 'active'),
(427, 1, 'done');
with ReversedScenarioCTE as
(
select
ID,
[status],
rowNumber = row_number() over (partition by ID order by ScenarioID desc)
from
@Scenario
)
select
M.ID,
M.[user],
M.Name,
S.[status]
from
@Master M
inner join ReversedScenarioCTE S on
M.ID = S.ID and
S.rowNumber = 1;
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