Mar*_* AJ 7 mysql sql sql-limit
我有这样一张桌子:
// notifications
+----+--------------+------+---------+------------+
| id | event | seen | id_user | time_stamp |
+----+--------------+------+---------+------------+
| 1 | vote | 1 | 123 | 1464174617 |
| 2 | comment | 1 | 456 | 1464174664 |
| 3 | vote | 1 | 123 | 1464174725 |
| 4 | answer | 1 | 123 | 1464174813 |
| 5 | comment | NULL | 456 | 1464174928 |
| 6 | comment | 1 | 123 | 1464175114 |
| 7 | vote | NULL | 456 | 1464175317 |
| 8 | answer | NULL | 123 | 1464175279 |
| 9 | vote | NULL | 123 | 1464176618 |
+----+--------------+------+---------+------------+
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我正在尝试为特定用户选择至少15行.只有两个条件:
始终所有未读的行(seen = NULL)都应匹配,即使它们超过15行.
如果未读行数大于15,则还应选择2个读取行(seen = 1).
示例: read是读取行unread的数量,是notifications表中未读行的数量.
read | unread | output should be
------|--------|-------------------------------------
3 | 8 | 11 rows
12 | 5 | 15 rows (5 unread, 10 read)
20 | 30 | 32 rows (30 unread, 2 read)
10 | 0 | 10 rows (0 unread, 10 read)
10 | 1 | 11 rows (1 unread, 10 read)
10 | 6 | 15 rows (6 unread, 9 read)
100 | 3 | 15 rows (3 unread, 12 read)
3 | 100 | 102 rows (100 unread, 2 read)
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这是我当前的查询,它不支持第二个条件.
SELECT id, event, seen, time_stamp
FROM notifications n
WHERE id_user = :id AND seen IS NULL
) UNION
(SELECT id, event, seen, time_stamp
FROM notifications n
WHERE id_user = :id
ORDER BY (seen IS NULL) desc, time_stamp desc
LIMIT 15
)
ORDER BY (seen IS NULL) desc, time_stamp desc;
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我找到解决方案。要添加第二个条件(如果未读行超过 15 行,则选择两个已读行),我必须再使用一个UNION。像这样的东西:
(SELECT id, event, seen, time_stamp
FROM notifications n
WHERE id_user = :id AND seen IS NULL
)UNION
(SELECT id, event, seen, time_stamp
FROM notification n
WHERE id_user = :id AND seen IS NOT NULL
LIMIT 2
)UNION
(SELECT id, event, seen, time_stamp
FROM notifications n
WHERE id_user = :id
ORDER BY (seen IS NULL) desc, time_stamp desc
LIMIT 15
)
ORDER BY (seen IS NULL) desc, time_stamp desc;
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第一个子查询获取所有未见的行。第二个得到两行可见的行。第三个有十五行。删除UNION重复项,但不应用其他限制。
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