这是我当前用于让用户登录的代码：
<?php
$uName = "";
$uNameMsg = "";
$pWord = "";
$pWordMsg = "";
if(isset($_POST["submit"])){
$uName = $_POST["username"];
if (empty($uName)) {
$uNameMsg = "please enter a username<br/>";
}
$pWord = $_POST["password"];
if (empty($pWord)) {
$pWordMsg = "please enter a password<br/>";
}
}
?>
//form goes here
<?php
require_once("conn.php");
$sql = "SELECT username, password FROM customers
WHERE username = $uName
AND password = $pWord";
$results = mysqli_query($conn, $sql)
or die ('Problem with query' . mysqli_error($conn));
if (mysqli_num_rows($results) < 1) {
echo "invalid username and password";
} else {
echo "query success, redirect header goes here";
}
?>
我收到一个语法错误，说 'AND password =' 子句是错误的。然后它说错误位于第 3 行，即我的标记，而“AND 密码 =”位于第 75 行。
这是我从第 1 行开始的代码：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Customer Login</title>
<link rel="stylesheet" href="customerlogin.css">
</head>
小智 5
你可以用这个。这肯定会奏效：
$sql = "SELECT username, password FROM customers
WHERE username = '$uName'
AND password = '$pWord'";
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