Pet*_*tte 6 deep-learning tensorflow deconvolution
我正在尝试堆叠2层来tf.nn.conv2d_transpose()对张量进行上采样.它在前馈期间工作正常,但在向后传播时出现错误:
ValueError: Incompatible shapes for broadcasting: (8, 256, 256, 24) and (8, 100, 100, 24).
基本上,我只是将第一个的输出设置conv2d_transpose为第二个的输入:
convt_1 = tf.nn.conv2d_transpose(...)
convt_2 = tf.nn.conv2d_transpose(conv_1)
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只使用一个conv2d_transpose,一切正常.只有多个conv2d_transpose堆叠在一起时才会出现错误.
我不确定实现多层的正确方法conv2d_transpose.任何关于如何解决这个问题的建议都将非常感激.
这是一个复制错误的小代码:
import numpy as np
import tensorflow as tf
IMAGE_HEIGHT = 256
IMAGE_WIDTH = 256
CHANNELS = 1
batch_size = 8
num_labels = 2
in_data = tf.placeholder(tf.float32, shape=(batch_size, IMAGE_HEIGHT, IMAGE_WIDTH, CHANNELS))
labels = tf.placeholder(tf.int32, shape=(batch_size, IMAGE_HEIGHT, IMAGE_WIDTH, 1))
# Variables
w0 = tf.Variable(tf.truncated_normal([3, 3, CHANNELS, 32]))
b0 = tf.Variable(tf.zeros([32]))
# Down sample
conv_0 = tf.nn.relu(tf.nn.conv2d(in_data, w0, [1, 2, 2, 1], padding='SAME') + b0)
print("Convolution 0:", conv_0)
# Up sample 1. Upscale to 100 x 100 x 24
wt1 = tf.Variable(tf.truncated_normal([3, 3, 24, 32]))
convt_1 = tf.nn.sigmoid(
tf.nn.conv2d_transpose(conv_0,
filter=wt1,
output_shape=[batch_size, 100, 100, 24],
strides=[1, 1, 1, 1]))
print("Deconvolution 1:", convt_1)
# Up sample 2. Upscale to 256 x 256 x 2
wt2 = tf.Variable(tf.truncated_normal([3, 3, 2, 24]))
convt_2 = tf.nn.sigmoid(
tf.nn.conv2d_transpose(convt_1,
filter=wt2,
output_shape=[batch_size, IMAGE_HEIGHT, IMAGE_WIDTH, 2],
strides=[1, 1, 1, 1]))
print("Deconvolution 2:", convt_2)
# Loss computation
logits = tf.reshape(convt_2, [-1, num_labels])
reshaped_labels = tf.reshape(labels, [-1])
cross_entropy = tf.nn.sparse_softmax_cross_entropy_with_logits(logits, reshaped_labels)
loss = tf.reduce_mean(cross_entropy)
optimizer = tf.train.GradientDescentOptimizer(0.5).minimize(loss)
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我想你需要在conv2d_transpose中改变你的'stride'参数.conv2d_transpos就像conv2d输入和输出相反.
因为conv2d,stride输入形状将决定输出形状.因为conv2d_transpose,stride输出形状将决定输入形状.现在你的步幅是[1 1 1 1],这意味着输出和输入conv2d_transpose大致相同(忽略边界效应).
对于输入H = W = 100 ,如果设置为SAME stride = [1 2 2 1],则输出conv2d_tranpose应为200.(反转conv2d)padding.简而言之,输入,输出和步幅需要兼容.
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