我有以下收藏
{
"_id" : ObjectId("57315ba4846dd82425ca2408"),
"myarray" : [
{
userId : ObjectId("570ca5e48dbe673802c2d035"),
point : 5
},
{
userId : ObjectId("613ca5e48dbe673802c2d521"),
point : 2
},
]
}
Run Code Online (Sandbox Code Playgroud)
如果userId不存在,我想进入myarray,它应该被附加到myarray.如果userId存在,则应将其更新为point.
db.collection.update({
_id : ObjectId("57315ba4846dd82425ca2408"), "myarray.userId" : ObjectId("570ca5e48dbe673802c2d035")
},{
$set: {"myarray.$.point": 10}
})
Run Code Online (Sandbox Code Playgroud)
但是如果userId不存在,则没有任何反应.
db.collection.update({
_id : ObjectId("57315ba4846dd82425ca2408")
},{
$push: {"myarray": {userId: ObjectId("570ca5e48dbe673802c2d035"), point: 10}}
})
Run Code Online (Sandbox Code Playgroud)
但是如果userId对象已经存在,它将再次推送.
在MongoDB中执行此操作的最佳方法是什么?
tur*_*hal 20
从MongoDB v4.2开始,有一个名为“使用聚合管道更新文档”的选项,
$cond是否userId存在myarray.userId$map迭代myarray数组循环并检查条件是否userId匹配,然后使用与新文档合并$mergeObjects$concatArrays连接新对象并myarraylet _id = ObjectId("57315ba4846dd82425ca2408");
let updateDoc = {
userId: ObjectId("570ca5e48dbe673802c2d035"),
point: 10
};
db.collection.update(
{ _id: _id },
[{
$set: {
myarray: {
$cond: [
{ $in: [updateDoc.userId, "$myarray.userId"] },
{
$map: {
input: "$myarray",
in: {
$mergeObjects: [
"$$this",
{
$cond: [
{ $eq: ["$$this.userId", updateDoc.userId] },
updateDoc,
{}
]
}
]
}
}
},
{ $concatArrays: ["$myarray", [updateDoc]] }
]
}
}
}]
)
Run Code Online (Sandbox Code Playgroud)
Yet*_*eti 17
Flying Fisher接受的答案是,现有记录将首先被删除,然后再次被推送.
一种更安全的方法(常识)是首先尝试更新记录,如果找不到匹配,请插入它,如下所示:
// first try to overwrite existing value
var result = db.collection.update(
{
_id : ObjectId("57315ba4846dd82425ca2408"),
"myarray.userId": ObjectId("570ca5e48dbe673802c2d035")
},
{
$set: {"myarray.$.point": {point: 10}}
}
);
// you probably need to modify the following if-statement to some async callback
// checking depending on your server-side code and mongodb-driver
if(!result.nMatched)
{
// record not found, so create a new entry
// this can be done using $addToSet:
db.collection.update(
{
_id: ObjectId("57315ba4846dd82425ca2408")
},
{
$addToSet: {
myarray: {
userId: ObjectId("570ca5e48dbe673802c2d035"),
point: 10
}
}
}
);
// OR (the equivalent) using $push:
db.collection.update(
{
_id: ObjectId("57315ba4846dd82425ca2408"),
"myarray.userId": {$ne: ObjectId("570ca5e48dbe673802c2d035"}}
},
{
$push: {
myarray: {
userId: ObjectId("570ca5e48dbe673802c2d035"),
point: 10
}
}
}
);
}
Run Code Online (Sandbox Code Playgroud)
这也应该给(常识,未经测试)性能提高,如果在大多数情况下记录已经存在,则只执行第一个查询.
Fly*_*her 10
试试这个
db.collection.update(
{ _id : ObjectId("57315ba4846dd82425ca2408")},
{ $pull: {"myarray.userId": ObjectId("570ca5e48dbe673802c2d035")}}
)
db.collection.update(
{ _id : ObjectId("57315ba4846dd82425ca2408")},
{ $push: {"myarray": {
userId:ObjectId("570ca5e48dbe673802c2d035"),
point: 10
}}
)
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
19575 次 |
| 最近记录: |