如何在foreach循环中从数组中拉出自定义对象的PHP/Eclipse中获得智能感知?

Edw*_*uay 10 php eclipse intellisense type-hinting code-completion

我在一个数组中有一组自定义对象(Podcast).

当我使用foreach循环迭代这个集合时,我没有对包含从集合中拉出的对象的变量进行代码完成(例如我在C#/ VisualStudio中).

有没有办法给PHP一个类型提示,以便Eclipse知道从集合中拉出的对象的类型,以便它可以向我展示intellisense中该对象的方法?

替代文字

<?php

$podcasts = new Podcasts();
echo $podcasts->getListHtml();

class Podcasts {
    private $collection = array();

    function __construct() {
        $this->collection[] = new Podcast('This is the first one');
        $this->collection[] = new Podcast('This is the second one');
        $this->collection[] = new Podcast('This is the third one');
    }

    public function getListHtml() {
        $r = '';
        if(count($this->collection) > 0) {
            $r .= '<ul>';
            foreach($this->collection as $podcast) {
                $r .= '<li>' . $podcast->getTitle() . '</li>';
            }
            $r .= '</ul>';
        }       
        return $r;
    }
}

class Podcast {

    private $title;

    public function getTitle() { return $this->title; }
    public function setTitle($value) {  $this->title = $value;}

    function __construct($title) {
        $this->title = $title;
    }

}

?>
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附录

谢谢,Fanis,我更新了我的FOREACH模板以自动包含该行:

if(count(${lines}) > 0) {
    foreach(${lines} as ${line}) {
        /* @var $$${var} ${Type} */

    }
}
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替代文字

Fan*_*nis 19

是的,试试:

foreach($this->collection as $podcast) {
    /* @var $podcast Podcast */
    $r .= '<li>' . $podcast->getTitle() . '</
}
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自从我使用Eclipse以来已经有一段时间,但我记得它曾经在那里工作过.