spyne SOAP Web 服务中的多个命名空间

Question

我正在尝试使用 Spyne 框架和此示例代码部分在 python3 中托管 SOAP 服务：

class HelloWorldService(ServiceBase):
    @srpc(Unicode, Integer, _returns=Iterable(Unicode))
    def say_hello(name, times):
        for i in range(times):
            yield 'Hello, %s' % name
application = Application([HelloWorldService],
    tns='spyne.examples.hello',
    in_protocol=Soap11(),
    out_protocol=Soap11()
)
if __name__ == '__main__':
    # You can use any Wsgi server. Here, we chose
    # Python's built-in wsgi server but you're not
    # supposed to use it in production.
    from wsgiref.simple_server import make_server
    wsgi_app = WsgiApplication(application)
    server = make_server('0.0.0.0', 8000, wsgi_app)
    server.serve_forever()

它可以工作，但它只使用一个命名空间，tns='spyne.examples.hello'.

我可以在这一行定义多个服务：

application = Application([HelloWorldService, OtherService1, OtherService2]

但是是否可以为每个服务定义不同的命名空间？像这样的东西是行不通的：

tns=['spyne.examples.hello', 'http://other.service1', 'http://other.service2']

Answer 1

您可以WsgiMounter为此使用类。

from spyne.util.wsgi_wrapper import WsgiMounter

app1 = Application([SomeService], tns=namespace1,
    in_protocol=Soap11(), out_protocol=Soap11())
app2 = Application([SomeOtherService], tns=namespace2,
    in_protocol=Soap11(), out_protocol=Soap11())
wsgi_mounter = WsgiMounter({
    'app1': app1,
    'app2': app2,
})

wsgi_mounter然后，在代码中传递对象而不是 wsgi_app ：

if __name__ == '__main__':
    from wsgiref.simple_server import make_server
    wsgi_mounter = WsgiMounter({
        'app1': app1,
        'app2': app2, 
    })
    server = make_server('0.0.0.0', 8000, wsgi_mounter)
    server.serve_forever()