Van*_*ran 23 java servlets servlet-filters
我的应用程序中有2个过滤器.基于某些条件,我想选择是否执行第二个过滤器.有没有办法做到这一点?
我做了一些谷歌搜索没有成功.我希望请求继续而不执行第二个过滤器.那可能吗?
任何帮助将不胜感激.
Bal*_*usC 58
除了科林的回答,还有另一种方式:只是不要打电话FilterChain#doFilter(),但是RequestDispatcher#forward().
if (condition) {
request.getRequestDispatcher(((HttpServletRequest) request).getServletPath()).forward(request, response);
} else {
chain.doFilter(request, response);
}
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但是这将跳过当前开启的所有过滤器,期待正在收听的过滤器<dispatcher>FORWARD</dispatcher>.
Col*_*ert 10
您可以在请求中设置属性,并在第二个过滤器中进行检查.
public class FirstFilter implements Filter {
//...
public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
servletRequest.setAttribute("executeSecondFilter", true);
//...
if(someReason)
servletRequest.setAttribute("executeSecondFilter", false);
filterChain.doFilter(servletRequest, servletResponse);
}
}
public class SecondFilter implements Filter {
//..
public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
if (servletRequest.getAttribute("executeSecondFilter") == null || !((Boolean) servletRequest.getAttribute("executeSecondFilter"))) {
filterChain.doFilter(servletRequest, servletResponse);
}
//...
}
}
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您可以像这样简化上面的代码:
public class FirstFilter implements Filter {
//...
public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
//...
if(someReason)
servletRequest.setAttribute("executeSecondFilter", false);
filterChain.doFilter(servletRequest, servletResponse);
}
}
public class SecondFilter implements Filter {
//..
public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
if (servletRequest.getAttribute("executeSecondFilter") != null) {
filterChain.doFilter(servletRequest, servletResponse);
}
//...
}
}
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这样您只需检查属性"executeSecondFilter"的存在