Jef*_*eff 5 javascript generator node.js ecmascript-6 es6-promise
我在 node.js 中有一个批处理作业: 将文件复制到目录中,对文件进行分析,然后删除文件。
我想迭代一系列作业并使用生成器暂停执行,直到批处理作业完成,然后再开始另一个作业。这是我到目前为止所拥有的:
const cars = ["toyota", "honda", "acura"];
function copyFilesAndRunAnalysis(car) {
return new Promise(function(resolve, reject) {
setTimeout(function() { // simulate some delay
resolve(); // control should return to generator here
}, 1000);
});
}
function* doCar(car) {
yield copyFilesAndRunAnalysis(car);
}
// BEGIN HERE
console.log('start here');
carBatch = doCar(cars[0]);
carBatch.next(); // confusion here!!!
carBatch.next(); // should this all be in a forEach loop?Run Code Online (Sandbox Code Playgroud)
我想做的是有一个 forEach 循环每辆车,完成该copyFilesAndRunAnalysis方法中的所有相应工作 - 暂停直到Promise.resolve()然后继续到下一辆。尝试 forEach 根本不会让任何东西运行。
您不使用.valueat jsat 问题。由 产生的对象的将从.value中返回,其中可以链接到,可以用于递归调用,直到没有项目保留在数组的原始或副本中。next()GeneratorPromisecopyFilesAndRunAnalysis.then().next().value()Array.prototype.shift()doCarcars
const cars = ["toyota", "honda", "acura"];
let carsCopy = cars.slice(0);
function copyFilesAndRunAnalysis(car) {
return new Promise(function(resolve, reject) {
setTimeout(function() { // simulate some delay
resolve(car); // control should return to generator here
}, 1000);
})
}
function* doCar(cars) {
yield copyFilesAndRunAnalysis(cars);
}
// BEGIN HERE
console.log("start here");
carBatch = doCar(carsCopy.shift());
carBatch.next().value.then(function re(data) {
console.log(data);
return carsCopy.length
? doCar(carsCopy.shift()).next().value.then(re)
: "complete"
})
.then(function(complete) {
console.log(complete);
})Run Code Online (Sandbox Code Playgroud)
注意,利用 、 递归可以实现相同的过程Promise;不使用Generator函数。
const cars = ["toyota", "honda", "acura"];
let carsCopy = cars.slice(0);
function copyFilesAndRunAnalysis(car) {
return new Promise(function(resolve, reject) {
setTimeout(function() { // simulate some delay
resolve(car); // control should return to generator here
}, 1000);
})
}
// BEGIN HERE
console.log("start here");
carBatch = copyFilesAndRunAnalysis(carsCopy.shift());
carBatch.then(function re(data) {
console.log(data);
return carsCopy.length
? copyFilesAndRunAnalysis(carsCopy.shift()).then(re)
: "complete"
})
// do stuff when all items within `cars` have been
// processed through `copyFilesAndRunAnalysis`
.then(function(complete) {
console.log(complete);
})Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
4115 次 |
| 最近记录: |