替换NSString中的多个字符组

Question

我想在一个NSString中替换几个不同的字符组.目前我正在使用几种重复方法,但我希望有一种方法可以在一种方法中执行此操作:

NSString *result = [html stringByReplacingOccurrencesOfString:@"<B&" withString:@" "];
NSString *result2 = [result stringByReplacingOccurrencesOfString:@"</B>" withString:@" "];

NSString *result3 = [result2 stringByReplacingOccurrencesOfString:@"gt;" withString:@" "];
return [result3 stringByReplacingOccurrencesOfString:@" Description  " withString:@""];

Answer 1

我认为SDK中没有任何内容,但您至少可以使用一个类别,因此您可以编写如下内容:

NSDictionary *replacements = [NSDictionary dictionaryWithObjectsAndKeys:
                                @" ", @"<B&",
                                @" ", @"</B>",
                                @" ", @"gt;"
                                @"" , @" Description  ",
                              nil];
return [html stringByReplacingStringsFromDictionary:replacements];

...通过使用以下内容:

@interface NSString (ReplaceExtensions)
- (NSString *)stringByReplacingStringsFromDictionary:(NSDictionary *)dict;
@end

@implementation NSString (ReplaceExtensions)
- (NSString *)stringByReplacingStringsFromDictionary:(NSDictionary *)dict
{
    NSMutableString *string = [self mutableCopy];
    for (NSString *target in dict) {
       [string replaceOccurrencesOfString:target withString:[dict objectForKey:target] 
               options:0 range:NSMakeRange(0, [string length])];
    }
    return [string autorelease];
}
@end

在带有ARC的现代Objective C中:

-(NSString*)stringByReplacingStringsFromDictionary:(NSDictionary*)dict
{
    NSMutableString *string = self.mutableCopy;
    for(NSString *key in dict)
        [string replaceOccurrencesOfString:key withString:dict[key] options:0 range:NSMakeRange(0, string.length)];
    return string.copy;
}