Sequelize GROUP BY 仅在主表上聚合，而不是在连接中的完整连接表上聚合

Question

我有五个表USER_ATTRIB，QUESTION_MAIN，REPLY_MAIN，CATEGORY_MAIN，QSTN_CATG如下一个相关的另一个问题：

m.QUESTION_MAIN.belongsTo(m.USER_ATTRIB, { foreignKey: 'POSTER_I', targetKey: 'USER_I'});
m.QUESTION_MAIN.hasMany(m.REPLY_MAIN, { foreignKey: 'QSTN_I' });
m.QUESTION_MAIN.belongsToMany(m.CATEGORY_MAIN, { through: m.QSTN_CATG, foreignKey: 'QSTN_I' });
m.QUESTION_MAIN.hasMany(m.QSTN_CATG, { foreignKey: 'QSTN_I' });

我想运行查询QUESTION_MAIN以获取有关问题的详细信息。需要的细节之一是问题的回复数量，可以通过以下方式查询

SELECT COUNT(REPLY_MAINs.QSTN_I) GROUP BY QSTN_I;

我要运行的组合查询是：

SELECT `QUESTION_MAIN`.*
       ,`USER_ATTRIB`.`USERATTRIB_ID` AS `USER_ATTRIB.USERATTRIB_ID`
       ,`USER_ATTRIB`.`USER_NAME` AS `USER_ATTRIB.USER_NAME`
       ,`QSTN_CATGs`.`QSTN_CATG_ID` AS `QSTN_CATGs.QSTN_CATG_ID`,
       ,`QSTN_CATGs`.`CATG_I` AS `QSTN_CATGs.QSTN_CATG_I`
       ,`REPLY_MAINs`.`REPLY_ID` AS `REPLY_MAINs.REPLY_ID`
       , COUNT(`REPLY_MAINs`.`QSTN_I`) AS `REPLY_MAINs.REPLY_COUNT`
FROM (
        SELECT `QUESTION_MAIN`.`QUESTION_ID`
               , ( 6371 * acos( cos( radians(13.0508629) ) * cos( radians( QSTN_LOC_LAT ) ) * cos( radians( QSTN_LOC_LONG ) - radians(77.6092108) ) + sin( radians(13.0508629) ) * sin( radians( QSTN_LOC_LAT ) ) ) ) AS `DISTANCE`
        FROM `QUESTION_MAIN` AS `QUESTION_MAIN` 
        WHERE (
                SELECT `QSTN_I` 
                FROM `QSTN_CATG` AS `QSTN_CATG` 
                WHERE (`QSTN_CATG`.`QSTN_I` = `QUESTION_MAIN`.`QUESTION_ID`) LIMIT 1 
                ) IS NOT NULL  
        HAVING `DISTANCE` < 5 
        ORDER BY `QUESTION_MAIN`.`CREATED` DESC LIMIT 3
        ) AS `QUESTION_MAIN` 
LEFT OUTER JOIN `USER_ATTRIB` AS `USER_ATTRIB` ON `QUESTION_MAIN`.`POSTER_I` = `USER_ATTRIB`.`USER_I` 
INNER JOIN `QSTN_CATG` AS `QSTN_CATGs` ON `QUESTION_MAIN`.`QUESTION_ID` = `QSTN_CATGs`.`QSTN_I` 
LEFT OUTER JOIN `REPLY_MAIN` AS `REPLY_MAINs` ON `QUESTION_MAIN`.`QUESTION_ID` = `REPLY_MAINs`.`QSTN_I` 
              AND `REPLY_MAINs`.`REPLY_STATUS` = 200
GROUP BY `QUESTION_ID` 
ORDER BY `QUESTION_MAIN`.`CREATED` DESC;

这是进行该查询的 Sequelize：

QUESTION_MAIN.findAll({
attributes:['QUESTION_ID', 'POSTER_I',
  ['( 6371 * acos( ' 
                  + 'cos( radians('+qstnFeedRequest.qstnLocLat+') ) ' 
                  + '* cos( radians( QSTN_LOC_LAT ) ) '
                  + '* cos( radians( QSTN_LOC_LONG ) - radians('+ qstnFeedRequest.qstnLocLong+') ) '
                  + '+ sin( radians('+qstnFeedRequest.qstnLocLat+') ) '
                  + '* sin( radians( QSTN_LOC_LAT ) ) ) '
  + ')', 'DISTANCE'
  ]
],
include: [
  { model: USER_ATTRIB, 
    attributes:['USER_NAME']
  },
  { model: QSTN_CATG, 
    attributes: [['CATG_I', 'QSTN_CATG_I']],
    where: qstnCatgWhereClause
  },
  { model: REPLY_MAIN, 
    attributes: [[sequelize.fn('COUNT', sequelize.col('REPLY_MAINs.QSTN_I')), 'REPLY_COUNT']], 
    where: {REPLY_STATUS: 200},
    required: false
  }
],
having:{ 'DISTANCE' : {$lt: 5} },
where: whereClause,
group: ['QUESTION_ID'],
limit: qstnFeedRequest.limit
})

问题是，GROUP BY正在应用条款内内查询，而不是对整个加盟：

SELECT `QUESTION_MAIN`.*,
   ...
FROM (
    SELECT `QUESTION_MAIN`.`QUESTION_ID`,
    ...  
    HAVING `DISTANCE` < 5 
    GROUP BY `QUESTION_ID` -- This should go outside
    ORDER BY `QUESTION_MAIN`.`CREATED` DESC LIMIT 3
    ) AS `QUESTION_MAIN` 
LEFT OUTER JOIN `USER_ATTRIB` ...
ORDER BY `QUESTION_MAIN`.`CREATED` DESC;

这导致计数错误聚合。无论我尝试什么，我都无法GROUP BY从内部查询中获取该子句。

如何对整个连接进行分组而不是单独对主表进行分组？

Answer 1

在网上摸索了半天，终于找到了解决办法。

正如链接在评论中的线程中所说，在连接之外进行限制的 1:M 查询是低效的。所以，Sequelize做单独的查询为1：1和1：M关系，因为 separate: true属性被设置在包括1的声明：M表。

即使在此之后，还有几个问题：

如果表的连接列未包含在属性中，则代码会中断。

Sequelizehaving也在内部表上应用外部子句。为了防止这种情况，我having在包含中添加了一个真实的声明。

这是我修改后的最终续集：

QUESTION_MAIN.findAll({
attributes:['QUESTION_ID', 'POSTER_I',
  ['( 6371 * acos( ' 
                  + 'cos( radians('+qstnFeedRequest.qstnLocLat+') ) ' 
                  + '* cos( radians( QSTN_LOC_LAT ) ) '
                  + '* cos( radians( QSTN_LOC_LONG ) - radians('+ qstnFeedRequest.qstnLocLong+') ) '
                  + '+ sin( radians('+qstnFeedRequest.qstnLocLat+') ) '
                  + '* sin( radians( QSTN_LOC_LAT ) ) ) '
  + ')', 'DISTANCE'
  ]
],
include: [
  { model: USER_ATTRIB, 
    attributes:['USER_NAME']
  },
  { model: QSTN_CATG, 
    attributes: [['CATG_I', 'QSTN_CATG_I']],
    where: qstnCatgWhereClause
  },
  { model: REPLY_MAIN, //this is the 1:M table
    attributes: ['QSTN_I', [sequelize.fn('COUNT', sequelize.col('REPLY_MAIN.QSTN_I')), 'REPLY_COUNT']], 
    //QSTN_I is the column joining QUESTION_MAIN and REPLY_MAIN. Not including this in the attributes throws an error 
    where: {REPLY_STATUS: 200},
    group: ['QSTN_I'], //grouping it in this query instead of the main query
    separate: true,//the culprit
    having: {'REPLY_COUNT': {$ne: null}}, //this is a dummy having clause which always returns true. This is added to stop the outer having clause being applied to the inner query
    required: false
  }
],
having:{ 'DISTANCE' : {$lt: 5} },
where: whereClause,
limit: qstnFeedRequest.limit
})

希望这可以节省某人的 2 天时间