我发现这个无效操作数错误到二进制+(有id*char*)

Question

NSString *queryString = [NSString
  stringWithFormat:@"http://202.164.43.57:82/iphoneWebservice/Service1.asmx/" + 
    "GetData?InsertData=%@", imageView.image];

Answer 1

您在此处使用的语法无效.它看起来像你试图连接字符串,这是你将如何去这样的:

NSString *queryString = [NSString stringWithFormat:@"http://202.164.43.57:82/iphoneWebservice/Service1.asmx/GetData?InsertData=%@", imageView.image];