我有一个简单关系的模型
class Tasks(models.Model):
initiator = models.ForeignKey(User, on_delete = models.CASCADE)
class TaskResponsiblePeople(models.Model):
task = models.ForeignKey('Tasks')
auth_user = models.ForeignKey(User)
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我需要编写一个SQL查询的模拟,如下所示:
select a.initiator, b.auth_user
from Tasks a
inner join TaskResponsiblePeople b
on TaskResponsiblePeople.task_id = task.id
where Tasks.initiator = 'value A' OR TaskResponsiblePeople.auth_user = 'value B'
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问题是OR语句处理两个不同的表,我不知道正确的Django语法来模仿上面提到的原始SQL查询.请帮帮我!
更新1
根据下面给出的答案,我使用以下代码:
people = TaskResponsiblePeople.objects.filter(Q(task__initiator = request.user.id)|Q(auth_user = request.user.id)).select_related('auth_user')
print people.query
# The result of the print copy-pasted from console
# SELECT * FROM `task_responsible_people`
# LEFT OUTER JOIN `tasks` ON (`task_responsible_people`.`task_id` = `tasks`.`id`)
# LEFT OUTER JOIN `auth_user` T4
# ON (`task_responsible_people`.`auth_user_id` = T4.`id`)
# WHERE (`tasks`.`initiator_id` = 7 OR
# 'task_responsible_people`.`auth_user_id` = 7)
tasks = Tasks.objects.prefetch_related(
Prefetch('task_responsible_people', queryset=people, to_attr='people'))
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但是,在最终结果集中,我仍然可以看到启动器和auth_user都不等于request.user的记录(在这种情况下等于7)我避免使用".values",因为可能需要序列化并将查询集转换为json .
我认为如果您只想要那些特定的列,您可以这样做:
from django.db.models import Q
qs = Tasks.objects.filter(Q(initiator=userA) | Q(taskresponsiblepeople__auth_user=userB))\
.values('initiator', 'taskresponsiblepeople__auth_user')
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要检查生成的查询,您可以查看:
print(qs.query)
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我的数据库中没有模型,但它应该生成类似于以下内容的查询:
SELECT "tasks"."initiator_id", "taskresponsiblepeople"."auth_user_id"
FROM "tasks" LEFT OUTER JOIN "taskresponsiblepeople"
ON ( "tasks"."id" = "taskresponsiblepeople"."tasks_id" )
WHERE ("tasks"."initiator_id" = userA_id
OR "taskresponsiblepeople"."auth_user_id" = userB_id))
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