PyQt入门

Question

我正在使用Python和Qt测试快速GUI编程中的一些示例,但在这里或其他地方遇到了绊脚石.当我复制到下面的练习时(逐字,从书中):

import sys
import time
from PyQt4.QtCore import *
from PyQt4.QtGui import *

app = QApplication(sys.argv)

try:
    due = QTime.currentTime()
    message = "Alert!"

    if len(sys.argv) < 2:
        raise ValueError

    hours, mins = sys.argv[1].split(":")
    due = QTime(int(hours), int(mins))

    if not due.isValid():
        raise ValueError
    if len(sys.argv) > 2:
        message = " ".join(sys.argv[2:])

except ValueError:
    message = "Usage: alert.pyw HH:MM [optional message*]" # 24hr Clock

while QTime.currentTime() < due:
    time.sleep(20) # 20 seconds

label = QLabel("<font color=red size=72><b>" + message + "</b></font>")

label.setWindowFlags(Qt.SplashScreen)
label.show()

QTimer.singleShot(60000, app.quit) # 1 minute

app.exec_()

我收到以下错误:

andy@ASUSix:~/Documents/Programming/Python/PyQt$ from: can't read /var/mail/PyQt4.QtCore
from: can't read /var/mail/PyQt4.QtGui
./alert.pyw: line 6: syntax error near unexpected token `('
./alert.pyw: line 6: `app = QApplication(sys.argv)

这里出了什么问题？我的PATH设置错误了吗？

Answer 1

您可能忘记在脚本中添加一个shebang,告诉shell使用Python解释器实际运行它.尝试添加

#!/usr/bin/python

作为脚本中的第一行,前提是安装了Python解释器.你可能想尝试一下

which python

万一你不确定.