获取变量的名称作为输入,并使用该名称更改变量

6 bash

我从脚本用户获取变量的名称作为第一个参数,并将所述变量的值回显给控制台:

#!/bin/bash
variablename=$1
echo "The value of $variablename is: " ${!variablename}
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这很棒!

我无法工作的是,如果我想将该变量更改为用户的第二个参数的值.语法错误的示例是:

#!/bin/bash
variablename=$1
echo "The value of $variablename is: " ${!variablename}
echo "I will now try to change the value into $2."
(!variablename}=$2
# The above line generates: {!variablename}=2: command not found
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换句话说:如果可能,我如何从用户获取变量名称并读取(已经解决)并写入所述变量?

小智 7

在请求帮助后几分钟我突然闪过,我想我有一个解决方案:

#!/bin/bash
variablename=$1
echo "The value of $variablename is: " ${!variablename}
echo "I will now try to change the value into $2."
eval "$variablename=$2"
echo "Success! $variablename now has the value ${!variablename}!"
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有用.有没有更好的办法?