获取完整层次结构路径的SQL查询

RKP*_*RKP 5 t-sql sql-server

我有一个包含三列NodeId,ParentNodeId,NodeName的表.对于每个节点,我想得到一个完整的路径,如"lvl1/lvl2/lvl3 ...",其中lvl1,lvl2和lvl3是节点名称.我在这个链接http://www.sql-server-helper.com/functions/get-tree-path.aspx找到了一个功能.但我想使用CTE或任何其他技术来提高效率.如果有可能以更好的方式实现这一点,请告诉我.提前致谢.

Joe*_*lli 6

这是一个CTE版本.

declare @MyTable table (
    NodeId int,
    ParentNodeId int,
    NodeName char(4)
)

insert into @MyTable
    (NodeId, ParentNodeId, NodeName)
    select 1, null, 'Lvl1' union all
    select 2, 1, 'Lvl2' union all
    select 3, 2, 'Lvl3'

declare @MyPath varchar(100)

;with cteLevels as (
    select t.NodeId, t.ParentNodeId, t.NodeName, 1 as level
        from @MyTable t
        where t.ParentNodeId is null
    union all
    select t.NodeId, t.ParentNodeId, t.NodeName, c.level+1 as level
        from @MyTable t
            inner join cteLevels c
                on t.ParentNodeId = c.NodeId
)
select @MyPath = case when @MyPath is null then NodeName else @MyPath + '/' + NodeName end
    from cteLevels
    order by level

select @MyPath
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RKP*_*RKP 5

我是这样解决的,与乔的解决方案非常相似。

    with cte (NodeId,NodeName,hierarchyPath)as
(
    select NodeId,NodeName, NodeName
    from Node
    where ParentNodeId is null 
    union all
    select n.NodeId, n.NodeName, CONVERT(varchar(256), cte.hierarchyPath + '/' + n.NodeName)
    from Node n
    join cte on n.ParentNodeId = cte.NodeId
)

select * 
from cte 
order by NodeId
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