xlt*_*ttj 4 php xpath simplexml
I try to use SimpleXML in combination with XPath to find nodes which contain a certain string.
<?php
$xhtml = <<<EOC
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="de" lang="de">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title>Test</title>
</head>
<body>
<p>Find me!</p>
<p>
<br />
Find me!
<br />
</p>
</body>
</html>
EOC;
$xml = simplexml_load_string($xhtml);
$xml->registerXPathNamespace('xhtml', 'http://www.w3.org/1999/xhtml');
$nodes = $xml->xpath("//*[contains(text(), 'Find me')]");
echo count($nodes);
Expected output: 2 Actual output: 1
When I change the xhtml of the second paragraph to
<p>
Find me!
<br />
</p>
then it works like expected. How has my XPath expression has to look like to match all nodes containing 'Find me' no matter where they are?
Using PHP's DOM-XML is an option, but not desired.
Thank's in advance!
这取决于你想做什么.您可以选择<p/>包含其中任何后代中"查找我"的所有元素
//xhtml:p[contains(., 'Find me')]
这将返回重复的,所以你没有指定类型的节点,那么它将返回<body/>并<html/>为好.
或者您可能希望任何包含子节点(不是后代)的节点包含"查找我"
//*[text()[contains(., 'Find me')]]
这个不会回来<html/>或<body/>.
我忘了提到.代表节点的全文内容.text()用于检索[文本节点的节点集].表达式的问题contains(text(), 'Find me')在于contains()只能处理字符串,而不能处理节点集,因此它会转换text()为第一个节点的值,这就是删除第一个节点的原因<br/>.