我刚开始学习期望脚本。我一直试图从我的输出中提取以下内容:
core.4046140998.01.10.133211
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使用使用以下命令的预期脚本。有人可以告诉我我哪里出错了吗?我想将整个字符串 ie(core.4046140998.01.10.133211*) 存储在一个变量中并用它执行一些操作。
expect -re {^(core)\.*} {puts $expect_out(0,string)}
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我是否必须导入任何包才能完成这项工作?
由于这是期望的,因此“core”可能出现在一行的开头,但不会出现在输入字符串的开头。展示:
$ expect
expect1.1> spawn sh
spawn sh
8043
expect1.2> send "echo core.1234\r"
expect1.3> exp_internal 1
expect1.4> expect -re {^core.*}
Gate keeper glob pattern for '^core.*' is 'core*'. Activating booster.
expect: does "" (spawn_id exp6) match regular expression "^core.*"? Gate "core*"? gate=no
sh-4.3$ echo core.1234
core.1234
sh-4.3$
expect: does "sh-4.3$ echo core.1234\r\ncore.1234\r\nsh-4.3$ " (spawn_id exp6) match regular expression "^core.*"? Gate "core*"? gate=yes re=no
expect: timed out
expect1.5> expect -re {(?n)^core.*}
Gate keeper glob pattern for '(?n)^core.*' is 'core*'. Activating booster.
expect: does "sh-4.3$ echo core.1234\r\ncore.1234\r\nsh-4.3$ " (spawn_id exp6) match regular expression "(?n)^core.*"? Gate "core*"? gate=yes re=yes
expect: set expect_out(0,string) "core.1234\r"
expect: set expect_out(spawn_id) "exp6"
expect: set expect_out(buffer) "sh-4.3$ echo core.1234\r\ncore.1234\r"
expect1.6> puts ">>>$expect_out(0,string)<<<"
<<<core.1234
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注意事项:
-re {^core.*}不匹配。我们看到“超时”消息注意我们试图匹配的内容:
expect: does "sh-4.3$ echo core.1234\r\ncore.1234\r\nsh-4.3$ " (spawn_id exp6) match regular expression "^core.*"? Gate "core*"? gate=yes re=no
# ............^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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它以我发送的命令开头,因此使用“普通”锚将不起作用
我期待的下一件事是-re {(?n)^core.*}。这确实匹配。
(?n)是一个很少使用的Tcl 正则表达式指令,它告诉正则表达式引擎我们想要“换行敏感”匹配。.不会匹配换行符并且(这里更相关)^可以在多行字符串中的换行符之后立即匹配(类似于$)puts命令的输出看起来很奇怪。这是由于$expect_out(0,string). 请注意这一点,并string trim根据需要使用这里的外卖课程是: