在python中打开一个JSON文件

Kel*_*ubi 4 python json

这是我第一次尝试在 Python 中使用 JSON 文件,虽然我已经阅读了很多关于这件事的东西,但我仍然很困惑。我想逐行读取名为 jason.json 的文件,将其存储到名为 data 的列表中,然后打印它。但是,我总是收到以下错误:

Traceback (most recent call last):
  File "try.py", line 6, in <module>
    data.append(json.loads(line))
  File "C:\Users\...\Python35\lib\json\__init__.py", line 319, in loads
    return _default_decoder.decode(s)
  File "C:\Users\...\Python35\lib\json\__init__.py", line 339, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Users\...\Python35\lib\json\__init__.py", line 355, in raw_decode
    obj, end = self.scan_once(s, idx)
  json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 2 column 1 (char 2)
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这是我的代码:

import json
data = []
with open('jason.json') as f:
    for line in f:
        data.append(json.loads(line))

print(data)
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这是 jason.json:

{
  "E(2,3)" : "A common Afro-Cuban drum pattern",
  "E(2,5)" : "A rhythm found in Greece",
  "E(3,4)" : "It is the archetypal pattern of the Cumbia from Colombia",
  "E(3,5)" : "Persian rhythm"
}
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先感谢您!

ald*_*nor 5

请注意,存储在其中的数据jason.json是字典而不是列表。所以,如果你想要一个元组列表,你可以这样做

with open('jason.json') as f:
    data = list(json.load(f).items())
print(data)
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这产生

[('E(3,5)', 'Persian rhythm'), ('E(3,4)', 'It is the archetypal pattern of the Cumbia from Colombia'), ('E(2,3)', 'A common Afro-Cuban drum pattern'), ('E(2,5)', 'A rhythm found in Greece')]
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