你怎么逃脱jsonpath中的@符号？

Question

给出一个像这样的json列表:

    {    
 "listRel:customFieldList": {
            "platformCore:customField": [
              {
                "@internalId": "801",
                "scriptId": "custentity_admin_contact_cweb",
                "@xsi:type": "platformCore:BooleanCustomFieldRef",
                "platformCore:value": "false"
              },
              {
                "@internalId": "712",
                "@scriptId": "custentity_bar_number",
                "@xsi:type": "platformCore:StringCustomFieldRef",
                "platformCore:value": "166493"
              },
              {
                "@internalId": "798",
                "@scriptId": "custentity_contact_type",
                "@xsi:type": "platformCore:SelectCustomFieldRef",
                "platformCore:value": {
                  "@internalId": "1",
                  "@typeId": "148",
                  "platformCore:name": "Attorney"
                }
              }
              ]
 }
}

如何在"custentity_bar_number"中选择值？166493？

这将帮助您,但前提是您在JSON中删除@scriptId前面的@符号.

$..['platformCore:customField'][?(@['scriptId'] == 'custentity_bar_number')]

所以我需要的是一种逃避json中@符号的方法,并做出类似这样的工作:

$..['platformCore:customField'][?(@['@scriptId'] == 'custentity_bar_number')]

我正在使用http://jsonpath.com/来尝试完成这项工作.

Answer 1

您显然需要使用十六进制代码（我认为这与解析表达式的方式有关）

$..['platformCore:customField'][?(@['\x40scriptId'] == 'custentity_bar_number')]