L. *_* W. 6 python django json django-rest-framework
我正在尝试从 MySQL 数据库中检索过滤列表。查询本身看起来不错,但返回的 JSON 显示如下:
[
{
"id": "0038",
"name": "Jane Doe",
"total_hrs_per_week": 6,
"timezone": "America/Los_Angeles"
},
{
"id": "0039",
"name": "John Doe",
"total_hrs_per_week": 10,
"timezone": "America/Los_Angeles"
}]
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当我需要构建的规范想要这个时:
{
"people":[
{
"id": "0038",
"name": "Jane Doe",
"total_hrs_per_week": 6,
"timezone": "America/Los_Angeles"
},
{
"id": "0039",
"name": "John Doe",
"total_hrs_per_week": 10,
"timezone": "America/Los_Angeles"
}]}
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这是我的序列化器
class PeopleListSerializer(serializers.ModelSerializer):
id = serializers.CharField(source='id')
name =serializers.CharField(source='name')
total_hrs_per_week = serializers.IntegerField(source='total_hrs_per_week')
timezone = serializers.CharField(source='timezone')
class Meta:
model = models.Person
fields = ('id','name','total_hrs_per_week','timezone')
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知道如何以这种方式包装返回的结果吗?
编辑:
我试着把它包装在另一个像这样的序列化器中
class PeopleListWrapperSerializer(serializers.Serializer):
people = PeopleListSerializer(many=True)
class Meta:
fields = ['people']
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但这会引发以下错误:
尝试获取
people
serializer 上的字段值时出现 AttributeErrorPeopleListWrapperSerializer
。序列化器字段可能命名不正确,并且与Person
实例上的任何属性或键都不匹配。原始异常文本是:“人”对象没有属性“人”。
您可以通过覆盖该list()
方法来做到这一点。
class PeopleListView(ListAPIView):
def list(self, request, *args, **kwargs):
# call the original 'list' to get the original response
response = super(PeopleListView, self).list(request, *args, **kwargs)
# customize the response data
response.data = {"people": response.data}
# return response with this custom representation
return response
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