Jus*_*ond 6 iterator vector rust
我试图用一系列值填充向量.为了计算第一个值,我需要计算第二个值,这取决于第三个值等.
let mut bxs = Vec::with_capacity(n);
for x in info {
let b = match bxs.last() {
Some(bx) => union(&bx, &x.bbox),
None => x.bbox.clone(),
};
bxs.push(b);
}
bxs.reverse();
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目前我只是使用前后填充向量v.push(x)
,然后使用反向向量v.reverse()
.有没有办法在一次通过中做到这一点?
有没有办法在一次通过中做到这一点?
如果您不介意调整矢量,则相对容易.
struct RevVec<T> {
data: Vec<T>,
}
impl<T> RevVec<T> {
fn push_front(&mut self, t: T) { self.data.push(t); }
}
impl<T> Index<usize> for RevVec<T> {
type Output = T;
fn index(&self, index: usize) -> &T {
&self.data[self.len() - index - 1]
}
}
impl<T> IndexMut<usize> for RevVec<T> {
fn index_mut(&mut self, index: usize) -> &mut T {
let len = self.len();
&mut self.data[len - index - 1]
}
}
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使用的解决方案unsafe
如下。不安全版本的速度比使用reverse()
. 这个想法是使用Vec::with_capacity(usize)
来分配向量,然后使用ptr::write(dst: *mut T, src: T)
将元素从后到前写入向量中。offset(self, count: isize) -> *const T
用于计算向量的偏移量。
extern crate time;
use std::fmt::Debug;
use std::ptr;
use time::PreciseTime;
fn scanl<T, F>(u : &Vec<T>, f : F) -> Vec<T>
where T : Clone,
F : Fn(&T, &T) -> T {
let mut v = Vec::with_capacity(u.len());
for x in u.iter().rev() {
let b = match v.last() {
None => (*x).clone(),
Some(y) => f(x, &y),
};
v.push(b);
}
v.reverse();
return v;
}
fn unsafe_scanl<T, F>(u : &Vec<T> , f : F) -> Vec<T>
where T : Clone + Debug,
F : Fn(&T, &T) -> T {
unsafe {
let mut v : Vec<T> = Vec::with_capacity(u.len());
let cap = v.capacity();
let p = v.as_mut_ptr();
match u.last() {
None => return v,
Some(x) => ptr::write(p.offset((u.len()-1) as isize), x.clone()),
};
for i in (0..u.len()-1).rev() {
ptr::write(p.offset(i as isize), f(v.get_unchecked(i+1), u.get_unchecked(i)));
}
Vec::set_len(&mut v, cap);
return v;
}
}
pub fn bench_scanl() {
let lo : u64 = 0;
let hi : u64 = 1000000;
let v : Vec<u64> = (lo..hi).collect();
let start = PreciseTime::now();
let u = scanl(&v, |x, y| x + y);
let end= PreciseTime::now();
println!("{:?}\n in {}", u.len(), start.to(end));
let start2 = PreciseTime::now();
let u = unsafe_scanl(&v, |x, y| x + y);
let end2 = PreciseTime::now();
println!("2){:?}\n in {}", u.len(), start2.to(end2));
}
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