删除URL中的旧参数(PHP)

Question

我正在使用PHP为表创建分页.我正在使用以下代码来创建分页链接

<a class='page-numbers' href='$href&pagenum=$i'>$i</a>

随$ href

$href = $_SERVER['REQUEST_URI'];

它运行良好,然而,它与地址栏混淆,每次添加一个新的pagenum参数.所以它变成了pagenum = 1&pagenum = 3&pagenum = 4 ....

如何改善？

Answer 1

How about this? Went and tested, to be sure :)

<?php
    $new_get = $_GET; // clone the GET array
    $new_get['pagenum'] = $i; // change the relevant parameter
    $new_get_string = http_build_query($new_get); // create the foo=bar&bar=baz string
?>
<a class="page-numbers" href="?<?php echo $new_get_string; ?>">
    <?php echo $i ?>
</a>

Also, note that the whole $href bit is unnecessary. If you start your href with ?, the browser will apply the query string to the current path.

I bet you're going to be looping, though, so here's a version optimized for producing 10,000 page number links. My benchmarks put it as being ever so slightly faster at large numbers of links, since you're just doing string concatenation instead of a full HTTP query build, but it might not be enough to be worth worrying about. The difference is only really significant when there five or six GET parameters, but, when there are, this strategy completes in about half the time on my machine.

<?php
    $pageless_get = $_GET; // clone the GET array
    unset($pageless_get['pagenum']); // remove the pagenum parameter
    $pageless_get_string = http_build_query($pageless_get); // create the foo=bar&bar=baz string
    for($i = 0; $i < 10000; $i++):
        // append the pagenum param to the query string
        $page_param = "pagenum=$i";
        if($pageless_get_string) {
            $pageful_get_string = "$pageless_get_string&$page_param";
        } else {
            $pageful_get_string = $page_param;
        }
?>
    <a class="page-numbers" href="?<?php echo $pageful_get_string; ?>">
        <?php echo $i ?>
    </a>
<?php endfor ?>