我正在尝试创建一个手动洗牌的方法.该列表被洗牌,但每次都会产生相同的结果.代码示例如下:
package ch11;
import java.util.ArrayList;
import java.util.Arrays;
public class Chapter_11_E07_ShuffleArrayList {
public static void main(String[] args) {
Integer[] array = {1, 2, 3, 4, 5, 6, 7, 8};
ArrayList<Integer> intList = new ArrayList<>(Arrays.asList(array));
System.out.println("Before shuffle: ");
for (Integer x: intList)
System.out.print(x + " ");
shuffle(intList);
System.out.println("\nAfter shuffle: ");
for (Integer x: intList)
System.out.print(x + " ");
}
public static void shuffle(ArrayList<Integer> intList) {
// Simple solution
// java.util.Collections.shuffle(intList);
// Manual shuffle
for (Integer x: intList) {
int newIndex = (int) Math.random() * intList.size();
Integer temp = intList.get(x);
intList.set(x, intList.get(newIndex));
intList.set(newIndex, temp);
}
}
}
Run Code Online (Sandbox Code Playgroud)
它似乎在某种程度上起作用,但Math.random * intList.size()每次产生相同的随机索引?输入非常感谢!
das*_*ght 12
这是因为
int newIndex = (int) Math.random() * intList.size();
Run Code Online (Sandbox Code Playgroud)
没有正确括号.它应该是
int newIndex = (int)(Math.random() * intList.size());
Run Code Online (Sandbox Code Playgroud)
为了避免像这样的简单错误,请创建新Random对象并调用nextInt(intList.size()).