pas*_*ros 15 iphone hash xcode objective-c sha256
当我使用此代码创建字符串的sha256时
unsigned char hashedChars[32];
NSString *inputString;
inputString = [NSString stringWithFormat:@"hello"];
NSData * inputData = [inputString dataUsingEncoding:NSUTF8StringEncoding];
CC_SHA256(inputData.bytes, inputData.length, hashedChars);
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它正确地返回哈希,但是我需要插入一个类似于\ x00\x25\x53的字符串,在这种情况下,该函数返回一个空字符串的sha256,因为指定的编码不能用于转换接收器.
现在,我的问题是:如何插入此特殊字符以生成正确的哈希?谢谢
Jag*_*war 40
试试这个,它对我有用
1)获取纯文本输入的哈希值
-(NSString*)sha256HashFor:(NSString*)input
{
const char* str = [input UTF8String];
unsigned char result[CC_SHA256_DIGEST_LENGTH];
CC_SHA256(str, strlen(str), result);
NSMutableString *ret = [NSMutableString stringWithCapacity:CC_SHA256_DIGEST_LENGTH*2];
for(int i = 0; i<CC_SHA256_DIGEST_LENGTH; i++)
{
[ret appendFormat:@"%02x",result[i]];
}
return ret;
}
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2)获取哈希NSData
作为输入
注意: -我使用了NSData
类别,因此代码如下
- (NSString *)SHA256_HASH {
//if (!self) return nil;
unsigned char hash[CC_SHA256_DIGEST_LENGTH];
if ( CC_SHA256([(NSData*)self bytes], [(NSData*)self length], hash) ) {
NSData *sha2 = [NSData dataWithBytes:hash length:CC_SHA256_DIGEST_LENGTH];
// description converts to hex but puts <> around it and spaces every 4 bytes
NSString *hash = [sha2 description];
hash = [hash stringByReplacingOccurrencesOfString:@" " withString:@""];
hash = [hash stringByReplacingOccurrencesOfString:@"<" withString:@""];
hash = [hash stringByReplacingOccurrencesOfString:@">" withString:@""];
// hash is now a string with just the 40char hash value in it
//NSLog(@"hash = %@",hash);
// Format SHA256 fingerprint like
// 00:00:00:00:00:00:00:00:00
int keyLength=[hash length];
NSString *formattedKey = @"";
for (int i=0; i<keyLength; i+=2) {
NSString *substr=[hash substringWithRange:NSMakeRange(i, 2)];
if (i!=keyLength-2)
substr=[substr stringByAppendingString:@":"];
formattedKey = [formattedKey stringByAppendingString:substr];
}
return formattedKey;
}
return nil;
}
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