Python：另一个函数从一个函数访问返回的值

Question

我是一般编程的新手，刚开始真正接触python。我正在做一个数字猜测项目。

import random

def main(): # main function
    print("Welcome to the number guesser game")
    range_func()
    max_guess_number(lower_range_cut, upper_range_cut)
    evaluation(random_number, total_guesses)

def range_func():   # allows user to select a range for the number guess
    print("Please select a range in which you would like to guess.")
    lower_range_cut = int(input("Lower boundary limit: "))
    global lower_range_cut
    upper_range_cut = int(input("Upper boundary limit: "))
    global upper_range_cut
    random_number = random.randint(lower_range_cut,upper_range_cut)
    global random_number
    return lower_range_cut, upper_range_cut, random_number

def max_guess_number(low,high): # returns the total number of guesses
    total_numbers = (high - low) + 1
    total_guesses = 0
    while (2**total_guesses) < total_numbers:
        total_guesses += 1
    print ("You have a total of %d guesses\n"
           "for your range between %d to %d"
           % (total_guesses, low, high))
    global total_guesses
    return total_guesses

def evaluation(random_number, total_guesses): # evaluates the users input
    guess_count = 0
    while guess_count < total_guesses:
        user_guess = int(input("Your guess: "))
        print("Your guess is: %d" % (user_guess))
        if (random_number == user_guess):
            print("You got it ")
            break
        elif user_guess > random_number:
            print("Guess lower!")
            guess_count += 1
        else:
            print("Guess higher!")
            guess_count += 1

if __name__ == "__main__":
    main()

我在编写该程序时遇到的一个问题是，如果不将每个变量重新定义为全局变量，就无法执行该程序。仅仅从一个函数返回值，就无法访​​问例如range_function的第二个返回变量upper_range_cut

有办法解决这个问题吗？

我也对代码本身的每条注释（可读性，函数使用，长度）感到高兴。我知道可以通过使用列表理解来使此代码缩短很多，但是我还没有真正看到这一领域的机会。

因此，感谢您的帮助！

乞力

Answer 1

你几乎在那里。您可以删除所有全局变量，然后将每个函数返回的值存储到局部变量中，然后将它们传递给新函数。

我在下面所做的唯一其他更改是：

• 如果正确猜出答案，则跳出评估循环。
• 如果在给定时间内没有找到猜测，则打印一条消息。请参阅：关于 Python while 语句的 Else 子句
• 底部两行允许从命令行运行脚本。请参阅：if __name__ == "__main__": do?

否则你看起来不错。

import random

def main(): # main function
    print("Welcome to the number guesser game")
    lower, upper, rand = range_func()
    total_guesses = max_guess_number(lower, upper)
    evaluation(rand, total_guesses)

def range_func():   # allows user to select a range for the number guess
    print("Please select a range in which you would like to guess.")
    lower_range_cut = int(input("Lower boundary limit: "))
    upper_range_cut = int(input("Upper boundary limit: "))
    random_number = random.randint(lower_range_cut, upper_range_cut)
    return lower_range_cut, upper_range_cut, random_number

def max_guess_number(low,high): # returns the total number of guesses
    total_numbers = (high - low) + 1
    total_guesses = 0
    while (2**total_guesses) < total_numbers:
        total_guesses += 1
    print ("You have a total of %d guesses\n"
           "for your range between %d to %d"
           % (total_guesses, low, high))

    return total_guesses

def evaluation(random_number, total_guesses): # evaluates the users input
    guess_count = 0
    while guess_count < total_guesses:
        guess_count += 1
        user_guess = int(input("Your guess: "))
        print("Your guess is: %d" % (user_guess))
        if (random_number == user_guess):
            print("You got it!")
            break
    else:
        print "Sorry, you didn't guess it in time. The answer was: %d" % random_number

if __name__ == '__main__':
    main()