Java Sound API - 捕获麦克风

Question

我已经阅读了Sound API for Java几天了,我无法理解它.我是一个不错的程序员,我只是很难理解API.

我一直试图从麦克风中捕获音频并实时显示波形图.

我在捕获音频方面遇到了麻烦,他们在教程中说这样做,但我似乎无法让它工作.

任何建议和帮助将不胜感激,逐行回答将是理想的.

谢谢,麻烦您了.

import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.TargetDataLine;

public class FindLine {

 public static void main (String[] args){

  AudioFormat format = new AudioFormat(22000,16,2,true,true);
  TargetDataLine line;
  DataLine.Info info = new DataLine.Info(TargetDataLine.class, 
      format); // format is an AudioFormat object
  if (!AudioSystem.isLineSupported(info)) {
      // Handle the error ... 
  }
  // Obtain and open the line.
  try {
      line = (TargetDataLine) AudioSystem.getLine(info);
      line.open(format);
  } catch (LineUnavailableException ex) {
      // Handle the error ... 
  }
 }

}

Answer 1

这将为您提供操作系统设置的默认值.

AudioFormat format = new AudioFormat(8000.0f, 16, 1, true, true);
TargetDataLine microphone = AudioSystem.getTargetDataLine(format);

要选择特定的输入设备(TargetDataLine),最好枚举混音器并过滤所需混音器的名称.

 Mixer.Info[] mixerInfos = AudioSystem.getMixerInfo();
 for (Mixer.Info info: mixerInfos){
  Mixer m = AudioSystem.getMixer(info);
  Line.Info[] lineInfos = m.getSourceLineInfo();
  for (Line.Info lineInfo:lineInfos){
   System.out.println (info.getName()+"---"+lineInfo);
   Line line = m.getLine(lineInfo);
   System.out.println("\t-----"+line);
  }
  lineInfos = m.getTargetLineInfo();
  for (Line.Info lineInfo:lineInfos){
   System.out.println (m+"---"+lineInfo);
   Line line = m.getLine(lineInfo);
   System.out.println("\t-----"+line);

  }

 }