如何在Koa 2中处理404？

Question

404.jade每当有无效的GET请求时,我都有一个我想要呈现的文件.

这是我目前的代码:

app.js

import Koa from 'koa'
import views from 'koa-views'
import serve from 'koa-static'
import rootRoutes from './routes/index'
import userRoutes from './routes/user'

const app = new Koa()

app.use(views(`${__dirname}/views`, { extension: 'jade' }))
app.use(serve(`${__dirname}/public`))
app.use(rootRoutes.routes())
app.use(userRoutes.routes())

app.listen(3000, () => {
  console.log('Server running at http://localhost:3000')
})

export default app

路线/ index.js

import Router from 'koa-router'
const router = new Router()

router.get('/', async ctx => {
  await ctx.render('index')
})

router.get('/about', async ctx => {
  await ctx.render('about')
})

export default router

路线/ user.js的

import Router from 'koa-router'
const router = new Router({ prefix: '/user' })

router.get('/:name', async ctx => {
  const user = ctx.params.name
  await ctx.render('user', { user })
})

export default router

如何处理任何类型的无效GET请求,并await ctx.render('404')在发生时以某种方式使用？

Answer 1

您可以middleware在app.js文件中添加自定义.

import Koa from 'koa'
import views from 'koa-views'
import serve from 'koa-static'
import rootRoutes from './routes/index'
import userRoutes from './routes/user'

const app = new Koa()

app.use(async(ctx, next) => {
  try {
    await next()
    const status = ctx.status || 404
    if (status === 404) {
        ctx.throw(404)
    }
  } catch (err) {
    ctx.status = err.status || 500
    if (ctx.status === 404) {
      //Your 404.jade
      await ctx.render('404')
    } else {
      //other_error jade
      await ctx.render('other_error')
    }
  }
})

app.use(views(`${__dirname}/views`, { extension: 'jade' }))
app.use(serve(`${__dirname}/public`))
app.use(rootRoutes.routes())
app.use(userRoutes.routes())

app.listen(3000, () => {
  console.log('Server running at http://localhost:3000')
})

export default app