Aru*_*agi 10 mongoose mongodb node.js
这是我的代码,以获得一个平面图并填充与此链接的所有单位
看下面的代码:
var floorplan = Floorplan.find({
project: req.params.project,
tower: req.params.tower,
isDeleted: false
});
floorplan.populate('flats').exec(function(err, floorplan) {
if (err) { return res.send(err); }
if (!floorplan) { return res.status(401).json(); }
res.status(200).json(floorplan);
});
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但是我想只填充那些isDeleted的单位:false如何实现这个?
平面图的架构
var FloorplanSchema = new Schema({
project: { type: Schema.ObjectId, ref: "Project" },
flats: [{ type: Schema.ObjectId, ref: "Flat" }],
tower: [{ type: Schema.ObjectId, ref: "Tower" }],
unitType: String,
area: Number,
floorPlan2D: String,
floorPlan3D: String,
livingRoomArea: Number,
kitchenArea: Number,
balconies: Number,
bathRooms: Number,
isDeleted: { type: Boolean, 'default': false },
createdAt: { type: Date, 'default': Date.now }
});
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平面图式
var FlatSchema = new Schema({
tower: { type: Schema.ObjectId, ref: "Tower" },
floorplan: { type: Schema.ObjectId, ref: "Floorplan" },
project: { type: Schema.ObjectId, ref: "Project" },
status: String,
floor: Number,
size: String,
superbuiltup_area: Number,
directionFacing: String,
furnishingState: String,
flooringType: String,
createdAt: { type: Date, 'default': Date.now },
isDeleted: { type: Boolean, 'default': false },
});
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chr*_*dam 22
该populate()方法有一个允许过滤的选项,你可以尝试这个
Floorplan
.find({
project: req.params.project,
tower: req.params.tower,
isDeleted: false
})
.populate({
path: 'flats',
match: { isDeleted: false }
})
.exec(function(err, floorplan) {
if (err) { return res.send(err); }
if (!floorplan) { return res.status(401).json(); }
res.status(200).json(floorplan);
});
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要么
Floorplan
.find({
project: req.params.project,
tower: req.params.tower,
isDeleted: false
})
.populate('flats', null, { isDeleted: false })
.exec(function(err, floorplan) {
if (err) { return res.send(err); }
if (!floorplan) { return res.status(401).json(); }
res.status(200).json(floorplan);
});
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