基于列的sklearn分层抽样

Muh*_*Zia 14 python pandas scikit-learn sklearn-pandas

我有一个包含亚马逊评论数据的相当大的CSV文件,我将其读入大熊猫数据框.我想将数据分成80-20(训练测试),但在这样做时我想确保分割数据按比例代表一列(类别)的值,即所有不同类别的评论都存在于列车中并按比例测试数据.

数据如下所示:

**ReviewerID**       **ReviewText**        **Categories**       **ProductId**

1212                   good product         Mobile               14444425
1233                   will buy again       drugs                324532
5432                   not recomended       dvd                  789654123 
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我使用以下代码来执行此操作:

import pandas as pd
Meta = pd.read_csv('C:\\Users\\xyz\\Desktop\\WM Project\\Joined.csv')
import numpy as np
from sklearn.cross_validation import train_test_split

train, test = train_test_split(Meta.categories, test_size = 0.2, stratify=y)
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它给出了以下错误

NameError: name 'y' is not defined
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因为我对python相对较新,所以我无法弄清楚我做错了什么,或者这个代码是否会根据列类别进行分层.当我从train-test split中删除了stratify选项以及categories列时,它似乎工作正常.

任何帮助将不胜感激.

nEO*_*nEO 20

    >>> import pandas as pd
    >>> Meta = pd.read_csv('C:\\Users\\*****\\Downloads\\so\\Book1.csv')
    >>> import numpy as np
    >>> from sklearn.model_selection import train_test_split
    >>> y = Meta.pop('Categories')
    >>> Meta
        ReviewerID      ReviewText  ProductId
        0        1212    good product   14444425
        1        1233  will buy again     324532
        2        5432  not recomended  789654123
    >>> y
        0    Mobile
        1     drugs
        2       dvd
        Name: Categories, dtype: object
    >>> X = Meta
    >>> X_train, X_test, y_train, y_test = train_test_split( X, y, test_size=0.33, random_state=42, stratify=y)
    >>> X_test
        ReviewerID    ReviewText  ProductId
        0        1212  good product   14444425
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su7*_*u7k 10

sklearn.model_selection.train_test_split

stratify:array-like或None(默认为None)

如果不是None,则数据以分层方式拆分,使用此作为类标签.

沿着API文档,我认为你必须尝试X_train, X_test, y_train, y_test = train_test_split(Meta_X, Meta_Y, test_size = 0.2, stratify=Meta_Y).

Meta_X,Meta_Y应该由您正确分配(我认为Meta_Y应该Meta.categories基于您的代码).

  • 警告,不赞成使用“ train_test_split”(请检查链接) (2认同)