正则表达拼图

Pan*_*sis 5 regex puzzle

这不是家庭作业,而是旧的考试问题.我很想知道答案.

我们给出一个字母S = {0,1,2,3,4,5,6,7,8,9,+}.将语言L定义为此字母表中的字符串集合w,使得w在L中,如果:

a)w是一个数字,如42 w是(有限的)数字之和,如34 + 16或34 + 2 + 10

b)w表示的数字可以被3整除.

为L写一个正则表达式(和DFA)

Mar*_*ers 6

这应该工作:

^(?:0|(?:(?:[369]|[147](?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147]0*(?:\+?(?:0\
+)*[369]0*)*\+?(?:0\+)*[258])*(?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[258]|0*(?:
\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147]0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147])|[
258](?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[258]0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0
\+)*[147])*(?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147]|0*(?:\+?(?:0\+)*[369]0*)
*\+?(?:0\+)*[258]0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[258]))0*)+)(?:\+(?:0|(?:(?
:[369]|[147](?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147]0*(?:\+?(?:0\+)*[369]0*)
*\+?(?:0\+)*[258])*(?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[258]|0*(?:\+?(?:0\+)*
[369]0*)*\+?(?:0\+)*[147]0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147])|[258](?:0*(?
:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[258]0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147])*
(?:0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[147]|0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)
*[258]0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*[258]))0*)+))*$

它的工作原理是有三个状态代表到目前为止模数为3的数字之和.它不允许在数字上加前导零,在字符串的开头和结尾加上符号,以及两个连续的加号.

生成正则表达式和试验台:

a = r'0*(?:\+?(?:0\+)*[369]0*)*\+?(?:0\+)*'
b = r'a[147]'
c = r'a[258]'

r1 = '[369]|[147](?:bc)*(?:c|bb)|[258](?:cb)*(?:b|cc)'
r2 = '(?:0|(?:(?:' + r1 + ')0*)+)'
r3 = '^' + r2 + r'(?:\+' + r2 + ')*$'
r = r3.replace('b', b).replace('c', c).replace('a', a)

print r

# Test on 10000 examples.

import random, re
random.seed(1)
r = re.compile(r)
for _ in range(10000):
    x = ''.join(random.choice('0123456789+') for j in range(random.randint(1,50)))
    if re.search(r'(?:\+|^)(?:\+|0[0-9])|\+$', x):
        valid = False
    else:
        valid = eval(x) % 3 == 0
    result = re.match(r, x) is not None
    if result != valid:
        print 'Failed for ' + x
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