将相同的函数与不同的参数结合起来 - Python

Question

我想制作一个tic tac toe游戏,我正在制作它,所以当用户输入数字1 - 9时,它会在网格上的相应空间上生成一个X. 这是函数:

def move(inp):
    if inp == 1:
        one = " X |\t|\n_____________\n   |\t|\n_____________\n   |\t|"
        print one
    elif inp == 2:
        two = "   | X |\n_____________\n   |\t|\n_____________\n   |\t|"
        print two
    elif inp == 3:
        three = "   |\t| X\n_____________\n   |\t|\n_____________\n   |\t|"
        print three
    elif inp == 4:
        four = "   |\t|\n____________\n X |\t|\n_____________\n   |\t|"
        print four
    elif inp == 5:
        five = "   |\t|\n_____________\n   | X  |\n_____________\n   |\t|"
        print five
    elif inp == 6:
        six = "   |\t|\n_____________\n   |\t| X \n_____________\n   |\t|"
        print six
    elif inp == 7:
        seven = "   |\t|\n_____________\n   |\t|\n_____________\n X |\t|"
        print seven
    elif inp == 8:
        eight = "   |\t|\n_____________\n   |\t|\n_____________\n   | X |"
        print eight
    elif inp == 9:
        nine = "   |\t|\n_____________\n   |\t|\n_____________\n   |\t| X "
        print nine

因此,网格显示X在正确的位置.但接下来的转折来了.我希望让他们输入一个新号码,但保留旧X的位置.我在想:有没有办法用不同的参数将该功能与自身结合起来并让它们在网格上放置两个X？所以,我的问题是,是否有一个功能,如果没有,我将如何做到这一点.

Answer 1

你可以这样做：

def make_square(inp):
    square = " {0} |{1}\t|{2}\n_____________\n  {3} | {4}\t|{5}\n_____________\n {6}  |{7}\t|{8}" # set {} brackets for 'X' format
    inp += -1 # rest because need take from 0 as the brackts indice
    for x in range(9): # range max of 'X'
        if x != inp:
            square = square.replace('{{{0}}}'.format(x),' ') # delete brackets without the number select by the user
            # {{ {0} }}  explication http://stackoverflow.com/a/5466478/4941927
    square = square.replace('{{{0}}}'.format(inp),'{0}') # convert current {number} into {0} for format
    square = square.format('X') # formatting brackets for the 'X'
    print square

make_square(2)

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