根据月份日期将季度列添加到数据表

Question

我正在使用data.table,我正在尝试创建一个名为"season"的新列,它会创建一个具有相应季节的列,例如夏天,冬天...基于名为"MonthName"的列.

我想知道是否有一种更有效的方法可以根据月份值将季节列添加到数据表中.

这是300,000个观测值中的前6个,假设该表被称为"dt".

    rrp         Year   Month Finyear hourminute AvgPriceByTOD MonthName
1: 35.27500     1999     1    1999      00:00      33.09037       Jan
2: 21.01167     1999     1    1999      00:00      33.09037       Jan
3: 25.28667     1999     2    1999      00:00      33.09037       Feb
4: 18.42334     1999     2    1999      00:00      33.09037       Feb
5: 16.67499     1999     2    1999      00:00      33.09037       Feb
6: 18.90001     1999     2    1999      00:00      33.09037       Feb

我试过以下代码:

dt[, Season :=  ifelse(MonthName = c("Jun", "Jul", "Aug"),"Winter", ifelse(MonthName = c("Dec", "Jan", "Feb"), "Summer", ifelse(MonthName = c("Sep", "Oct", "Nov"), "Spring" , ifelse(MonthName = c("Mar", "Apr", "May"), "Autumn", NA))))]

哪个回报:

 rrp totaldemand   Year Month Finyear hourminute AvgPriceByTOD MonthName Season
1: 35.27500     1999     1    1999      00:00      33.09037       Jan     NA
2: 21.01167     1999     1    1999      00:00      33.09037       Jan Summer
3: 25.28667     1999     2    1999      00:00      33.09037       Feb Summer
4: 18.42334     1999     2    1999      00:00      33.09037       Feb     NA
5: 16.67499     1999     2    1999      00:00      33.09037       Feb     NA
6: 18.90001     1999     2    1999      00:00      33.09037       Feb Summer

我收到错误:

Warning messages:
1: In MonthName == c("Jun", "Jul", "Aug") :
  longer object length is not a multiple of shorter object length
2: In MonthName == c("Dec", "Jan", "Feb") :
  longer object length is not a multiple of shorter object length
3: In MonthName == c("Sep", "Oct", "Nov") :
  longer object length is not a multiple of shorter object length
4: In MonthName == c("Mar", "Apr", "May") :
  longer object length is not a multiple of shorter object length 

除此之外,由于我不知道的原因,一些夏季月份被正确分配为"夏季",但其他月份被指定为NA,例如第1行和第2行应该都是夏天,但返回方式不同.

提前致谢!

Answer 1

一种非常直接的方法是使用查找表将月份名称映射到季节:

# create a named vector where names are the month names and elements are seasons
seasons <- rep(c("winter","spring","summer","fall"), each = 3)
names(seasons) <- month.abb[c(6:12,1:5)] # thanks thelatemail for pointing out month.abb
seasons
#     Jun      Jul      Aug      Sep      Oct      Nov      Dec      Jan 
#"winter" "winter" "winter" "spring" "spring" "spring" "summer" "summer" 
#     Feb      Mar      Apr      May 
#"summer"   "fall"   "fall"   "fall" 

用它:

dt[, season := seasons[MonthName]]

数据:

dt <- setDT(read.table(text="    rrp         Year   Month Finyear hourminute AvgPriceByTOD MonthName
1: 35.27500     1999     1    1999      00:00      33.09037       Jan
2: 21.01167     1999     1    1999      00:00      33.09037       Jan
3: 25.28667     1999     2    1999      00:00      33.09037       Feb
4: 18.42334     1999     2    1999      00:00      33.09037       Feb
5: 16.67499     1999     2    1999      00:00      33.09037       Feb
6: 18.90001     1999     2    1999      00:00      33.09037       Feb",
   header = TRUE, stringsAsFactors = FALSE))

Answer 2

有点打字,但代码很有效

dt[MonthName %in% c("Jun","Jul","Aug"), Season := "Winter"]
dt[MonthName %in% c("Dec","Jan","Feb"), Season := "Summer"]
dt[MonthName %in% c("Sep","Oct","Nov"), Season := "Spring"]
dt[is.na(MonthName), Season := "Autumn"]

在这里,我们通过引用分配一个子集 data.table

我更喜欢这个嵌套ifelses

如果要检查值是否在向量中,则必须使用%in%.看到不同的行为:

myVec <- c("a","b","c")

"a" == myVec
[1] TRUE FALSE FALSE

"a" %in% myVec
[1] TRUE