Div*_*mmy 2 javascript node.js
我有一个Node.js模块,它导出两个函数init(data),其中数据是Buffer,而test(word),其中word是一个字符串.
我想在test()函数中逐行读取数据Buffer实例中的行.
我没有Node.js的经验,只有JS.我从这个堆栈中了解到的是如何从Node.js模块中导出多个函数.
到目前为止这是函数声明.:
module.exports = {
init: function(data) {
},
test: function(word) {
}
}
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根据你的评论,data是instanceof Buffer,它包含一个字典,每行一个英文单词.所以,现在你可以转换data为字符串数组,按新行字符拆分.与module格式:
module.exports.init = function (data) {
if (!(data instanceof Buffer)) {
throw new Error('not a instanceof Buffer');
}
this.currentData = data.toString().split(/(?:\r\n|\r|\n)/g);
};
module.exports.test = function (word) {
// for example
var yourTestMethod = function (lineNumber, lineContent, testWord) {
return true;
};
if (this.currentData && this.currentData.length) {
for (var line = 0; line < this.currentData.length; line++) {
if (yourTestMethod(line, this.currentData[line], word)) {
return true;
}
}
}
return false;
};
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如果将此代码保存为testModule.js,则可以在主代码中使用此模块,如:
// load module
var testModule = require('./testModule.js');
// init
var buf = new Buffer(/* load dictionaly */);
testModule.init(buf);
// test
console.log(testModule.test('foo'));
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我认为这更简单.谢谢.
(老回答)
我想你可以使用readline模块.但是readline接受a stream,而不是a buffer.所以它需要转换.例如.
var readline = require('readline');
var stream = require('stream');
// string to buffer
var baseText = 'this is a sample text\n(empty lines ...)\n\n\n\nend line:)';
var buf = new Buffer(baseText);
// http://stackoverflow.com/questions/16038705/how-to-wrap-a-buffer-as-a-stream2-readable-stream
var bufferStream = new stream.PassThrough();
bufferStream.end(buf);
var rl = readline.createInterface({
input: bufferStream,
});
var count = 0;
rl.on('line', function (line) {
console.log('this is ' + (++count) + ' line, content = ' + line);
});
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然后输出是:
> node test.js
this is 1 line, content = this is a sample text
this is 2 line, content = (empty lines ...)
this is 3 line, content =
this is 4 line, content =
this is 5 line, content =
this is 6 line, content = end line:)
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那个怎么样?