如何为JSP配置spring boot mvc app？

Question

我是Spring boot(和servlet 3.0)的新手.我试图用JSP作为视图创建spring mvc项目.当我从我的控制器返回一个视图时,它没有被解析为JstlView.

这是我做的:

@SpringBootApplication
public class MyApp extends SpringBootServletInitializer {

    public static void main(String[] args) {
        SpringApplication.run(MyApp.class, args);
    }

}

---

@Controller
public class MainController {

    @RequestMapping( value="/main" , method = RequestMethod.GET  )
    public String main(){
        return "main";
    }

    @RequestMapping( value="/" , method = RequestMethod.GET  )
    public String welcome(){
        return "welcome";
    }
}

---

在src\main\webapp\WEB-INF\jsp.中创建了两个.jsp文件.

谷歌搜索后我发现我需要在application.properties中指定这个,所以我在props中添加了以下内容:

---

spring.mvc.view.prefix: /WEB-INF/jsp/
spring.mvc.view.suffix: .jsp


logging.level.org.springframework: TRACE
logging.level.com: TRACE

即使在此之后它也无法正常工作.这是痕迹.

2016-04-24 19:54:49.016 TRACE 7880 --- [nio-8080-exec-1] .w.s.m.m.a.ServletInvocableHandlerMethod : Invoking [MainController.welcome] method with arguments []
2016-04-24 19:54:49.016 TRACE 7880 --- [nio-8080-exec-1] .w.s.m.m.a.ServletInvocableHandlerMethod : Method [welcome] returned [welcome]
2016-04-24 19:54:49.020 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.s.v.ContentNegotiatingViewResolver : Requested media types are [text/html, application/xhtml+xml, image/webp, application/xml;q=0.9, */*;q=0.8] based on Accept header types and producible media types [*/*])
2016-04-24 19:54:49.020 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.servlet.view.BeanNameViewResolver  : No matching bean found for view name 'welcome'
2016-04-24 19:54:49.022 DEBUG 7880 --- [nio-8080-exec-1] o.s.b.f.s.DefaultListableBeanFactory     : Invoking afterPropertiesSet() on bean with name 'welcome'
2016-04-24 19:54:49.022 TRACE 7880 --- [nio-8080-exec-1] o.s.w.s.v.InternalResourceViewResolver   : Cached view [welcome]
2016-04-24 19:54:49.022 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.s.v.ContentNegotiatingViewResolver : Returning [org.springframework.web.servlet.view.InternalResourceView: name 'welcome'; URL [/WEB-INF/jsp/welcome.jsp]] based on requested media type 'text/html'
2016-04-24 19:54:49.022 DEBUG 7880 --- [nio-8080-exec-1] o.s.web.servlet.DispatcherServlet        : Rendering view [org.springframework.web.servlet.view.InternalResourceView: name 'welcome'; URL [/WEB-INF/jsp/welcome.jsp]] in DispatcherServlet with name 'dispatcherServlet'
2016-04-24 19:54:49.022 TRACE 7880 --- [nio-8080-exec-1] o.s.w.servlet.view.InternalResourceView  : Rendering view with name 'welcome' with model {} and static attributes {}
2016-04-24 19:54:49.026 DEBUG 7880 --- [nio-8080-exec-1] o.s.w.servlet.view.InternalResourceView  : Forwarding to resource [/WEB-INF/jsp/welcome.jsp] in InternalResourceView 'welcome'
2

正如您在跟踪中看到的,这是尝试将/jsp/welcome.jsp解析为InternalResourceView而不是JstlView.最终它以404失败了.

我需要遵循哪些其他步骤？是否有任何使用jsp的SpringBoot-mvc教程？

PS我可以使用web.xml(在我的配置文件中使用JstlView)使用jsp创建spring mvc app.但是我找不到任何有关使用jsp的Spring boot mvc的教程.

Answer 1

@Bean
public ViewResolver getViewResolver(){
    InternalResourceViewResolver resolver = new InternalResourceViewResolver();
    resolver.setPrefix("/WEB-INF/jsp/");
    resolver.setSuffix(".jsp");
    resolver.setViewClass(JstlView.class);
    return resolver;
}

也需要你的页面应该是/ webapp/WEB-INF/jsp /

+

    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-tomcat</artifactId>
    </dependency>
    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-jasper</artifactId>
    </dependency>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>jstl</artifactId>
    </dependency>

Answer 2

假设它是嵌入式Tomcat，

你需要在你的 pom.xml

    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-jasper</artifactId>
        <scope>provided</scope>
    </dependency>
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>jstl</artifactId>
    </dependency>

嵌入式 Tomcat 核心包没有 JSP 渲染支持。