将printf设为printf x [i] where为i的实际值而不是"x [i]"

Question

我学习C和尝试,我写了一个小程序.

#include <stdlib.h>
#include <stdio.h>

int main(void) 
{
int *x = malloc(sizeof(int)*3);
int i;
for(i=0;i<3; i++){
   x[i] = i*i;
   printf("x[i] = %d\n", x[i]);
   }
free(x);
}

现在输出是(ofc it)

x [i] = 0
x [i] = 1
x [i] = 4

我的问题是,我如何更改代码以获得输出？

x [0] = 0
x [1] = 1
x [2] = 4

Answer 1

printf("x[%d] = %d\n",i, x[i]);