rol*_*asi 7 python telegram-bot telepot
我只是实现了一个简单的机器人,该机器人应该将一些照片和视频发送给我chat_id。好吧,我正在使用python,这是脚本
import sys
import time
import random
import datetime
import telepot
def handle(msg):
chat_id = msg['chat']['id']
command = msg['text']
print 'Got command: %s' % command
if command == 'command1':
bot.sendMessage(chat_id, *******)
elif command == 'command2':
bot.sendMessage(chat_id, ******)
elif command == 'photo':
bot.sendPhoto(...)
bot = telepot.Bot('*** INSERT TOKEN ***')
bot.message_loop(handle)
print 'I am listening ...'
while 1:
time.sleep(10)
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在这一行中,bot.sendphoto我将插入chat_id图像的路径和,但是什么也没有发生。
我哪里错了?
谢谢
Maj*_*d A 19
如果您有本地图像路径:
bot.send_photo(chat_id, photo=open('path', 'rb'))
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如果您有来自互联网的图片网址:
bot.send_photo(chat_id, 'your URl')
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Run Code Online (Sandbox Code Playgroud)import telepot bot = telepot.Bot('______ YOUR TOKEN ________') # here replace chat_id and test.jpg with real things bot.sendPhoto(chat_id, photo=open('test.jpg', 'rb'))
小智 6
我也尝试过使用请求从 python 发送。也许是迟到的答案,但把它留在这里给像我这样的其他人..也许它会使用..我subprocess像这样成功了:
def send_image(botToken, imageFile, chat_id):
command = 'curl -s -X POST https://api.telegram.org/bot' + botToken + '/sendPhoto -F chat_id=' + chat_id + " -F photo=@" + imageFile
subprocess.call(command.split(' '))
return
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小智 6
我在使用python-telegram-bot发送图像和标题时使用了以下命令:
context.bot.sendPhoto(chat_id=chat_id, photo=
"url_of_image", caption="This is the test photo caption")
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Just using the Requests lib you can do it:
def send_photo(chat_id, file_opened):
method = "sendPhoto"
params = {'chat_id': chat_id}
files = {'photo': file_opened}
resp = requests.post(api_url + method, params, files=files)
return resp
send_photo(chat_id, open(file_path, 'rb'))
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