我有三个表:页面,附件,页面附件
我有这样的数据:
page
ID NAME
1 first page
2 second page
3 third page
4 fourth page
attachment
ID NAME
1 foo.word
2 test.xsl
3 mm.ppt
page-attachment
ID PAGE-ID ATTACHMENT-ID
1 2 1
2 2 2
3 3 3
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我想在该数字为0时获得每页的附件数量.我尝试过:
select page.name, count(page-attachment.id) as attachmentsnumber
from page
inner join page-attachment on page.id=page-id
group by page.id
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我得到这个输出:
NAME ATTACHMENTSNUMBER
second page 2
third page 1
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我想得到这个输出:
NAME ATTACHMENTSNUMBER
first page 0
second page 2
third page 1
fourth page 0
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如何获得0部分?
Mat*_*ton 28
将"内部联接"更改为"左外部联接",这意味着"获取联接左侧的所有行,即使右侧没有匹配的行".
select page.name, count(page-attachment.id) as attachmentsnumber
from page
left outer join page-attachment on page.id=page-id
group by page.name
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这是使用子查询的另一种解决方案.
SELECT
p.name,
(
SELECT COUNT(*) FROM [page-attachment] pa
WHERE pa.[PAGE-ID] = p.id
) as attachmentsnumber
FROM page p
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