Xcode UI Testing允许系统警报系列

Question

我有问题,如果我尝试允许系列系统警报,只工作一次,下一个警报不"允许"我谷歌搜索更多时间,并知道该帖子:(Xcode 7 UI测试:如何解雇一系列系统警报代码)没什么..不行.这是我当前的代码,首先警告"允许"成功,未检测到下一个警报..

XCUIApplication *app = [[XCUIApplication alloc] init];
app.launchEnvironment = @{
        @"isUITest" : @YES,
        @"withFakeData" : fakeData
};
[app launch];


for (int i = 1; i <= self.possibleSystemAlerts; i++) {
    NSLog(@"%d", i);
    XCTestExpectation *expectation = [self expectationWithDescription:@"High Expectations"];
    id monitor = [self addUIInterruptionMonitorWithDescription:@"Push notifications" handler:^BOOL(XCUIElement *_Nonnull interruptingElement) {
        XCUIElement *element = interruptingElement;
        XCUIElement *allow = element.buttons[@"Allow"];
        XCUIElement *ok = element.buttons[@"OK"];

        if ([ok exists]) {
            [ok tap];
            [expectation fulfill];
            return YES;
        }

        if ([allow exists]) {
            [allow forceTap];
            [expectation fulfill];
            return YES;
        }
        return NO;
    }];
    [app tap];
    [self waitForExpectationsWithTimeout:6.0 handler:^(NSError *error) {
        if (error) {
            NSLog(@"Timeout Error: %@", error);
        }
    }];
    [self removeUIInterruptionMonitor:monitor];
}

最好的问候,伊万.

UPD:

好吧,我发现解决方案,如何第一个警报后,尝试为这个网站紧随其后(感谢:http://www.it1me.com/it-answers?id=32148965&s=Template:Viper&ttl=Xcode+7+UI+Testing% 3A +如何+ + +消除+ a +系列+ +系统+警报+ +代码)只需要返回总是NO.

但另一个问题......

    t =    10.18s                     Find: Descendants matching type Alert
    t =    10.18s                     Find: Identity Binding
    t =    11.19s                     Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 1)
    t =    11.19s                         Snapshot accessibility hierarchy for com.apple.springboard
    t =    11.26s                         Find: Descendants matching type Alert
    t =    11.26s                         Find: Identity Binding
    t =    12.27s                     Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 2)
    t =    12.27s                         Snapshot accessibility hierarchy for com.apple.springboard
    t =    12.33s                         Find: Descendants matching type Alert
    t =    12.34s                         Find: Identity Binding
    t =    12.42s                     Assertion Failure: UI Testing Failure - No matches found for "Allow “MyApp” to access your location while you use the app?" Alert
Query input was {(
    Alert 0x7febe8731630: traits: 72057602627862528, {{25.0, 193.0}, {270.0, 182.0}}, label: '“MyApp” Would Like to Send You Notifications'
)}

他尝试关闭第三个通知,而不是第二个,当然他没有找到这个系统警报......

Answer 1

在应用启动之前逐个创建警报处理程序.此外,tap()在与警报交互之前,请确保应用程序中的任何位置.这是Xcode中的已知错误.

addUIInterruptionMonitor(withDescription:"First Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

addUIInterruptionMonitor(withDescription:"Second Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

addUIInterruptionMonitor(withDescription:"Third Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

let app = XCUIApplication()
app.launch()

app.tap()
app.tap()
app.tap()

这三个水龙头将连续启动每个警报处理程序,而不会实际触发您的应用程序中的任何事件.另请注意,每个中断处理程序都不会指定有关警报的任何内容,只会指定确认按钮.