NATVIS是否可以使用递归元组(可变模板)?

Ale*_*lex 2 natvis

我从这里实现了元组:https : //voidnish.wordpress.com/2013/07/13/tuple-implementation-via-variadic-templates/

可以使用NATVIS对其进行可视化吗?我到了

<Type Name="tuple">
  <DisplayString>()</DisplayString>  
</Type>

<Type Name="tuple&lt;*&gt;">
  <DisplayString>({_Myfirst})</DisplayString>
</Type>
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如何获取多个类型的_Myfirst值,以获取

<Type Name="tuple&lt;*,*&gt;">
  <DisplayString>({_Myfirst}, {???})</DisplayString>
</Type>

<Type Name="tuple&lt;*,*,*&gt;">
  <DisplayString>({_Myfirst}, {???}, {???})</DisplayString>
</Type>
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等等?

Gra*_*ers 5

您必须对类型进行一些修改才能使其正常工作。所需要的是一个base_typetypedef。

// tuple 
template<class... _Types> class tuple;

// empty tuple
template<> class tuple<> {};

// recursive tuple definition
template<class _This,
class... _Rest>
class tuple<_This, _Rest...>
    : private tuple<_Rest...>
{
public:
    typedef tuple<_Rest...> base_type; // ***** Added this line

    _This _Myfirst;
};
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现在,我们可以使用natvis声明来递归评估基本类型:

<!-- Handle empty tuples -->
<Type Name="tuple&lt;&gt;">
    <DisplayString>()</DisplayString>
    <Expand/>
</Type>

<!-- Handle a single parameter (this is also our terminator for recursion) -->
<Type Name="tuple&lt;*&gt;">
    <DisplayString IncludeView="noparens">{_Myfirst}</DisplayString>
    <DisplayString ExcludeView="noparens">({_Myfirst})</DisplayString>
    <Expand>
        <Item Name="Value">_Myfirst</Item>
    </Expand>
</Type>

<!-- Handle 2 or more items -->
<Type Name="tuple&lt;*,*&gt;">
    <!-- show the first item and then recurse by casting this to 'base_type' -->
    <DisplayString IncludeView="noparens">{_Myfirst}, {*(base_type *)this,view(noparens)}</DisplayString>
    <!-- Wrap our display string that doesn't a have any parentheses, this will be only done for the top level tuple -->
    <DisplayString ExcludeView="noparens">({*this,view(noparens)})</DisplayString>
    <Expand>
        <!-- Show the top level item -->
        <Item Name="Value">_Myfirst</Item>
        <!-- Recursively expand our base types -->
        <ExpandedItem>*(base_type *)this</ExpandedItem>
    </Expand>
</Type>
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结果如下:

元组.natvis结果