Dan*_*nin 1 haskell protocol-buffers
通常我知道如何修复模糊的类型变量问题,但这次不知道.长话短说,我使用protobuf Haskell库来处理协议缓冲区.该库让您忘记维护单独的.proto文件,如果它分别是Encode和Decode类型的实例,它会导致序列化和反序列化您的数据类型.
我正在protobuf之上设计一个简单的协议.主消息数据类型包含消息ID,消息类型和一些取决于类型的可选数据.我想要一个获取消息ID,消息类型和可选数据(需要是Encode类的实例)的函数,并创建一个新的MyMessage实例,并将可选数据预先序列化为ByteString.
这就是我尝试这样做的方式:
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE DeriveGeneric #-}
import Data.ByteString (ByteString)
import Data.Int
import Data.Maybe
import Data.Monoid
import Data.ProtocolBuffers
import Data.Serialize
import Data.Text (Text, pack)
import GHC.Generics (Generic)
import GHC.TypeLits
data MyMsgType = MSG_TYPE_1
| MSG_TYPE_2
deriving (Enum, Show)
data MyMessage = MyMessage {
msgId :: Required 1 (Value Int64)
, msgType :: Required 2 (Enumeration MyMsgType)
, cpData :: Optional 3 (Value ByteString)
} deriving (Generic, Show)
instance Encode MyMessage
instance Decode MyMessage
createMessage :: Encode a => Int64 -> MyMsgType -> Maybe a -> MyMessage
createMessage msgId msgType optionalData =
MyMessage (putField msgId) (putField msgType) (putField $ serialiseOptionalData optionalData)
serialiseMessage :: MyMessage -> ByteString
serialiseMessage = runPut . encodeLengthPrefixedMessage
serialiseOptionalData :: Encode a => Maybe a -> Maybe ByteString
serialiseOptionalData Nothing = Nothing
serialiseOptionalData (Just ctx) =
Just . runPut . encodeLengthPrefixedMessage $ ctx
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当我尝试使用createMessage函数时,我收到以下错误:
?> createMessage 1 MSG_TYPE_1 Nothing
<interactive>:7:1:
No instance for (Encode a0) arising from a use of ‘createMessage’
The type variable ‘a0’ is ambiguous
Note: there are several potential instances:
instance Encode MyMessage -- Defined at test.hs:24:10
instance Encode
(unordered-containers-0.2.6.0:Data.HashMap.Base.HashMap
protobuf-0.2.1.0:Data.ProtocolBuffers.Wire.Tag
[protobuf-0.2.1.0:Data.ProtocolBuffers.Wire.WireField])
-- Defined in ‘protobuf-0.2.1.0:Data.ProtocolBuffers.Encode’
In the expression: createMessage 1 MSG_TYPE_1 Nothing
In an equation for ‘it’: it = createMessage 1 MSG_TYPE_1 Nothing
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有人可以解释为什么会出现这个错误以及如何解决它?我没有得到编译器看到歧义的确切位置.
您需要提供有关可选数据类型的更多信息.当您使用Nothing类型的值时Maybe a,编译器无法确定究竟a是什么类型.您可以通过显式提供类型来修复它Nothing,如(Nothing :: Maybe Foo).
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