我有一个带有一些angularjs验证的Raw表单,
<form name = "sform" novalidate="true">
<table border="0">
<tr>
<td>
First name:
</td>
<td>
<input type="text" name="fname" ng-model="fname" placeholder="First Name" required="true" ng-pattern="/^[A-Za-z]*$/">
</td>
<td ng-show="sform.fname.$invalid && !sform.fname.$pristine" class="help-block">wrong name </td>
</tr>
<tr>
<td>
Last Name:
</td>
<td>
<input type="text" ng-model="lname" placeholder="last Name" required="true" ng-pattern="/^[A-Za-z]*$/">
</td>
<td ng-show= "sform.lname.$invalid && !sform.lname.$pristine" class="help-block">wrong Last name </td>
</tr>
<tr>
<td>
Email:
</td>
<td>
<input type="email" ng-model="email" placeholder="email" required="true">
</td>
<td ng-show="sform.email.$invalid && !sform.email.$pristine" class="help-block">wrong Email </td>
</tr>
<tr>
<td>
<button type="submit" ng-disabled="sform.$invalid" ng-click = "submitForm()">Submit</button>
</td>
</tr>
</table>
</form>
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相关的.js文件是
far_app.js
var farLogin = angular.module('far_login',[]);
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far_formcontroler.js
farLogin.controller('far_formcontrol',['$scope','$http',function($scope,$http) {
$scope.url='http://localhost/far_submit.php';
var config = {
headers : {
'Content-Type': 'application/x-www-form-urlencoded;charset=utf-8;'
}
}
// function to submit the form after all validation has occurred
$scope.submitForm = function() {
alert('our form is amazing'+$scope.fname+' '+$scope.email+' '+$scope.lname);
// check to make sure the form is completely valid
if ($scope.sform.$valid) {
$http.post($scope.url,{"name": $scope.fname, "email": $scope.email, "lname": $scope.lname},config).
success(function() {
alert('our form is amazing'+$scope.fname+' '+$scope.email+' '+$scope.lname);
})
}
else
{
alert('our form is not amazing');
}
}
}]);
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我的php文件是
<?php
header("Access-Control-Allow-Origin: *");
?>
<script type="text/javascript"> alert("this is php")</script>
<?php
?>
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但是php脚本根本没有执行,并且它们在浏览器的控制台中没有错误.
我哪里错了?
谢谢.
在SO本身的Angular $ http帖子问题上有几个好的线程,例如看看以下线程:如何在AngularJS中用$ http发布urlencoded表单数据?或者这一个:我如何将数据作为表单数据而不是请求有效负载发布?
注意:您需要在本地使用Web服务器运行此操作.下面的代码对我来说是"好的",我做了如下:
php -S 0.0.0.0:8181,访问index.html:http:// localhost:8181 /提交表单,它返回给我一个json响应:{"status":"OK","data":{"userid":null}}Pastebin:far_app.js,index.html,far_login.php
我使用PHP内置服务器仅用于测试目的,但是,我强烈建议您在Windows上使用像Wampp或Xampp之类的东西来运行它.您也可以手动配置Apache/PHP/Mysql,但是,Wampp/Xampp非常易于安装和使用.
我重新构建了一些代码,如下所示:
angular.module('far_login',[])
.controller('far_formcontrol',['$scope','$http', function($scope, $http) {
// function to submit the form after all validation has occurred
$scope.submitForm = function() {
console.log('First Name : ' , $scope.fname);
console.log('Email : ' , $scope.email);
console.log('Last Name: ', $scope.lname);
// check to make sure the form is completely valid
if ($scope.sform.$valid) {
$http({
url: 'http://localhost:8181/far_submit.php',
method: 'POST',
headers: {'Content-Type': 'application/x-www-form-urlencoded'},
transformRequest: function(obj) {
var str = [];
for(var p in obj)
str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
return str.join("&");
},
data: {"name": $scope.fname, "email": $scope.email, "lname": $scope.lname}
})
.then(function(response) {
console.log(response)
})
.catch(function (error) {
console.log(error);
});
} else {
alert('our form is not amazing');
}
};
}]);
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这是基于Plunker从 角文档,以及 far_submit.php文件,如:
<?php
header("Access-Control-Allow-Origin: *");
header('Content-Type: application/json');
$data = [ 'status' => 'OK', 'data' => [ 'userid' => $autogeneratedUserId] ];
echo json_encode($data);
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确保可以从http://localhost/far_submit.php访问far_submit.php