Google Places API - 返回无效的街道号码

Question

如果我使用地点ID 搜索500 Buckingham Place, Eight Mile PlainsGoogle Places API返回.如果我然后对该地点进行详细调用,则返回.500 Buckingham Place, Eight Mile Plains, Queensland, AustraliaEj41MDAgQnVja2luZ2hhbSBQbGFjZSwgRWlnaHQgTWlsZSBQbGFpbnMsIFF1ZWVuc2xhbmQsIEF1c3RyYWxpYQBuckingham Pl, Eight Mile Plains QLD 4113, Australia

这可以在Google地图网站上复制,网址为https://www.google.com.au/maps/search/500+Buckingham+Place+Eight+Mile+Plains.返回的地方就是Buckingham Pl, Eight Mile Plains QLD 4113, Australia.

我可以让Google Places API仅返回实际街道号码的搜索结果吗？

编辑 我正在做的电话是https://maps.googleapis.com/maps/api/place/autocomplete/json?input=500%20Buckingham%20Place%2C%20Eight%20Mile%20Plains&types=address