我对c ++很新,我非常接近解决方案,但我仍然需要一些帮助.我的循环第一次正常工作.之后,当我输入车号时,它似乎在某处抓取一些输入,并在第二遍时执行无效颜色.显然,我错过了什么,但我不知所措.任何帮助,将不胜感激.
这只是我程序的一小部分,但是存在问题:
while (count < 3)
{
cout << endl << "Enter car color: blue, red or green in lower case. ";
getline(cin, carColor[count]);
if (!(carColor[count] == "blue" || carColor[count] == "red" || carColor[count] == "green"))
{
cout << "That is an invalid color"
<< "The program will exit";
cin.clear();
cin.ignore();
return 0;
}
cout << endl << "Enter car number between 1 and 99: ";
cin >> carNumber[count]; // Enter car number
if (carNumber[count] >99 || carNumber[count] < 1)
{
cout << "That is not a correct number"
<< " The program will exit";
return 0;
}
cout << "car no is:" << carNumber[count] << "color: " << carColor[count];
++count;
// int lapCount{ 1 };
cout << endl;
}
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'\n'按 Enter 键后的字符可能cin >> carNumber[count];仍然保留,因此在执行第二遍后getline(cin, carColor[count]);您会得到一个空字符串。一种解决方案是这样做:
char c;
cin >> carNumber[count];
cin >> c;
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但更好的解决方案就是改变:
getline(cin, carColor[count]);
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到:
cin >> carColor[count];
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