ita*_*lov -4 java arrays average
我想用数组计算平均数.我希望程序要求成绩数量,并在我想要提供成绩数字之后.
在我想获得平均输出之后double.
到目前为止这是我的代码:
public class Average {
public static void main(String[] args)
{
//int n = MyConsole.readInt("Enter number of grades: " );
int a = MyConsole.readInt("Enter grade 1: " );
int b = MyConsole.readInt("Enter grade 2: " );
int c = MyConsole.readInt("Enter grade 3: " );
int[] numbers = new int[]{a,b,c};
numbers[0] = a;
numbers[1] = b;
numbers[2] = c;
int sum = 0;
for(int i=0; i < numbers.length ; i++)
sum = sum + numbers[i];
double average = sum / numbers.length;
System.out.println("Average value of array elements is : " + average);
}
}
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不知道你班级MyConsole在做什么,但我猜是Scanner:
您的代码改进将是这样的:
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter number of grades: " );
int n = sc.nextInt();
int sum = 0;
for (int i = 0; i < n; i++) {
System.out.print("Enter grade "+ (i + 1) + ": ");
int a = sc.nextInt();
sum += a;
}
double average = sum / n;
System.out.println("Average value of array elements is : " + average);
}
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输出(2级):
Enter number of grades: 2
Enter grade 1: 1
Enter grade 2: 5
Average value of array elements is : 3.0
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输出(5个等级):
Enter number of grades: 5
Enter grade 1: 10
Enter grade 2: 20
Enter grade 3: 30
Enter grade 4: 10
Enter grade 5: 50
Average value of array elements is : 24.0
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double average = sum / n;
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执行int分区,所以你不会有任何小数位!我建议快速演员:
double average = sum / (double) n;
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随着新的输出:
Enter number of grades: 2
Enter grade 1: 1
Enter grade 2: 4
Average value of array elements is : 2.5
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GUESS使用你自己的班级:
public static void main(String[] args) {
int sum = 0;
int n = MyConsole.readInt("Enter number of grades: " );
for (int i = 0; i < n; i++) {
int a = MyConsole.readInt("Enter grade "+ (i + 1) + ": ");
sum += a;
}
double average = sum / n;
System.out.println("Average value of array elements is : " + average);
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