工厂男孩随机选择一个字段选项"选择"的字段

Question

当Django模型中的字段具有选项选项时,请参阅Django选项字段选项,它使用包含2个项目的可迭代的迭代来定义允许的值.例如:

楷模

class IceCreamProduct(models.Model):
    PRODUCT_TYPES = (
        (0, 'Soft Ice Cream'),
        (1, 'Hard Ice Cream'),
        (2, 'Light Ice Cream'),
        (3, 'French Ice Cream'),
        (4, 'Italian-style Gelato'),
        (5, 'Frozen Dairy Dessert'),
    )
    type = models.PositiveSmallIntegerField('Type', choices=PRODUCT_TYPES, default=0)

要在Factory Boy中生成随机值以供选择,我将使用factory.fuzzy.FuzzyChoice,但这只选择2个项目的可迭代.它不能采用所选迭代的第一项.例如:

工厂

class IceCreamProductFactory(factory.django.DjangoModelFactory):
    class Meta:
        model = IceCreamProduct

    type = factory.fuzzy.FuzzyChoice(IceCreamProduct.PRODUCT_TYPES)

错误

TypeError: int() argument must be a string, a bytes-like object or a number, not 'tuple'

获取元组的第一项是不可能的.例如:

工厂

class IceCreamProductFactory(factory.django.DjangoModelFactory):
    class Meta:
        model = IceCreamProduct

    type = factory.fuzzy.FuzzyChoice(IceCreamProduct.PRODUCT_TYPES)[0]

错误

TypeError: 'FuzzyChoice' object does not support indexing

使用默认的Python随机迭代器是可能的,但这会在声明时生成一个值,因此每个工厂对象都将具有相同的随机值.例如:

工厂

class IceCreamProductFactory(factory.django.DjangoModelFactory):
    class Meta:
        model = IceCreamProduct

    type = random.choice(IceCreamProduct.PRODUCT_TYPES)][0]

如何在Factory Boy中解决这个问题？我是否需要创建自定义FuzzyAttribute？(如果是,请举个例子)

Answer 1

你不需要FuzzyAttribute.

您可以限制可能的值,只通过执行以下操作,将每个产品类型的int值赋予FuzzyChoice:

PRODUCT_IDS = [x[0] for x in IceCreamProduct.PRODUCT_TYPES]
class IceCreamProductFactory(factory.django.DjangoModelFactory):
    class Meta:
        model = IceCreamProduct

    type = factory.fuzzy.FuzzyChoice(PRODUCT_IDS)

它应该做的工作.

请注意,模糊模块最近已被弃用,请参阅(https://factoryboy.readthedocs.org/en/latest/fuzzy.html),您可能希望使用LazyFunction.

Answer 2

这是我使用factory.LazyFunctionlothiraldan建议的方法：

import random

...


def get_license_type():
    "Return a random license type from available choices."
    lt_choices = [x[0] for x in choices.LICENSE_TYPE_CHOICES]
    return random.choice(lt_choices)


def get_line_type():
    "Return a random line type from available choices."
    lt_choices = [x[0] for x in choices.LINE_TYPE_CHOICES]
    return random.choice(lt_choices)


class ProductFactory(ModelFactory):
    name = factory.Faker('name')
    description = factory.Faker('text')
    license_type = factory.LazyFunction(get_license_type)
    line_type = factory.LazyFunction(get_line_type)

    class Meta:
        model = 'products.ProductBaseV2'

Answer 3

因为我必须为相当多的模型这样做，所以我想出了一个更抽象的 erichonkanen 解决方案。我定义了一个辅助类，将其放在项目的顶级测试目录中，并将其导入包含工厂的模块：

test/helpers.py

import factory
import random


class ModelFieldLazyChoice(factory.LazyFunction):
    def __init__(self, model_class, field, *args, **kwargs):
        choices = [choice[0] for choice in model_class._meta.get_field(field).choices]
        super(ModelFieldLazyChoice, self).__init__(
            function=lambda: random.choice(choices),
            *args, **kwargs
        )

并在 app/factories.py

from app.models import IceCreamProduct
from test.helpers import ModelFieldLazyChoice

class IceCreamProductFactory(factory.django.DjangoModelFactory):
    class Meta:
        model = IceCreamProduct

    type = ModelFieldLazyChoice(IceCreamProduct, 'type')

Answer 4

你可以这样简单

class IceCreamProductFactory(factory.django.DjangoModelFactory):
    type = factory.Faker(
        'random_element', elements=[x[0] for x in IceCreamProduct.PRODUCT_TYPES]
    )

    class Meta:
        model = IceCreamProduct

PS。不要type用作属性