显示包含父类别的类别表

Gag*_*ags 5 php mysql mysqli

下面是我的表格结构:

菜单表

id   title  position
--------------------    
1    Test    home
2    Test2   home   
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类别

cid   name   parent  parent_menu
--------------------------------
 1    ABC      0         1
 2    DEF      0         2
 3    GHI      1         0
 4    JKL      2         0
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类别说明

id    cat_id    catdesc   slug
-------------------------------
 1      1       ABC_DESC   abc
 2      2       DEF_DESC   def
 3      3       GHI_DESC   ghi
 4      4       JKL_DESC   jkl    
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  • Menu table 处理菜单标题的位置.
  • Category table处理类别名称和其他参数.(如果parent = 0则表示这是主要类别,依此类推......)
  • Category Description table 处理描述,slug和其他参数.

现在我想显示如下数据

 Name      Description      Edit         Delete        /*table headings*/
-------------------------------------------------------
  Menu Title: (Test)    Main Category Name: (ABC)      
 ------------------------------------------------------
 GHI       GHI_DESC      edit_icon       delete_icon
 ______________________________________________________
  Menu Title: (Test2)    Main Category Name: (DEF)
 ------------------------------------------------------
  JKL       JKL_DESC      edit_icon       delete_icon
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我尝试使用JOINS并在PHP中操作数据,但没有运气.

SELECT * FROM `category` t1 LEFT JOIN `category_description` t2 ON t1.cid = t2.cat_id WHERE 1
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然后在PHP中我尝试如下

<?php $i = 1; foreach($subcat as $sub) { ?>
     <?php if($sub->parent == 0) { ?>
       <tr><td><?php echo $sub->name ?></td></tr>
     <?php } ?>
     <?php if($sub->parent != 0) { ?>
       <tr><td><?php echo $sub->name ?></td><td><?php echo $sub->catdesc ?></td>
       <td>Edit</td><td>Delete</td></tr>
     <?php } ?>
<?php } ?>
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以上打印表格如下:

Main Category Name: ABC
Main Category Name: DEF
------
GHI  GHI_DESC
JKl  JKL_DESC
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请根据需要建议如何打印.

Maw*_* HL 1

假设parent_menu来自菜单表中的id,请尝试以下操作:

SELECT t1.title, t2.name, t2.parent, t2.parent_menu, t3.catdesc
FROM menu t1
LEFT JOIN category t2 ON t1.id=t2.parent_menu
LEFT JOIN description t3 ON t2.cid=t3.cat_id
GROUP BY t2.name
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