将音频文件拆分为多个文件,每个文件都低于大小阈值

Ben*_*ler 2 unix audio ffmpeg flac

我有一个FLAC文件,我需要将其拆分为几个不同的FLAC文件,每个文件的大小必须低于100 MB.有没有可以为我做这个的UNIX工具?我可以自己实现这个逻辑吗?

旁注:由于FLAC是压缩的,我认为最简单的解决方案需要先将文件转换为WAV.

Ani*_*l_M 5

你的问题分为两部分.

  • 将现有FLAC音频文件转换为其他格式wav
  • 将转换后的wav文件拆分为特定大小的块.

显然,有不止一种方法可以做到这一点.但是,pydub提供了更容易实现上述方法.有关pydub文档的详细信息,请访问此处.

1)将现有FLAC音频文件转换为其他格式wav

使用pydub您可以阅读FLAC 音频格式,然后转换wav为如下

flac_audio = AudioSegment.from_file("sample.flac", "flac")
flac_audio.export("audio.wav", format="wav")
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2)将转换后的wav文件拆分为特定大小的块.

同样,有各种方法可以做到这一点.我这样做的方法是确定转换的总长度和大小,wavfile然后将其近似为所需的块大小.

使用的样品 wav file具有 101,612 KB大小并且大约589 sec或稍过9 minutes.

通过观察Wav文件大小:

立体声frame_rate 44.1KHz音频文件大约每分钟10 Mb.48K会有点大.这意味着相应的单声道文件将是每分钟5兆

对于我们的样本文件,近似值适用于每分钟约10 Mb

通过数学Wav文件大小:

wav文件大小和持续时间之间的关系由下式给出

wav_file_size_in_bytes = (sample rate (44100) * bit rate (16-bit) * number of channels (2 for stereo) * number of seconds) / 8 (8 bits = 1 byte)

资料来源:http://manual.audacityteam.org/o/man/digital_audio.html

我用来计算音频文件块的公式:

通过以下方法获取块大小

for duration_in_sec (X) we get wav_file_size (Y)
So whats duration in sec (K) given file size of 10Mb

这给了 K = X * 10Mb / Y

pydub.utils具有make_chunks可以制作特定持续时间(in milliseconds)的块的方法.我们使用上面的公式确定所需大小的持续时间

我们使用它来创建10Mb(或接近10Mb)的块并分别导出每个块.根据大小,最后一个块可能会更小.

这是一个有效的代码.

from pydub import AudioSegment
#from pydub.utils import mediainfo
from pydub.utils import make_chunks
import math

flac_audio = AudioSegment.from_file("sample.flac", "flac")
flac_audio.export("audio.wav", format="wav")
myaudio = AudioSegment.from_file("audio.wav" , "wav")
channel_count = myaudio.channels    #Get channels
sample_width = myaudio.sample_width #Get sample width
duration_in_sec = len(myaudio) / 1000#Length of audio in sec
sample_rate = myaudio.frame_rate

print "sample_width=", sample_width 
print "channel_count=", channel_count
print "duration_in_sec=", duration_in_sec 
print "frame_rate=", sample_rate
bit_rate =16  #assumption , you can extract from mediainfo("test.wav") dynamically


wav_file_size = (sample_rate * bit_rate * channel_count * duration_in_sec) / 8
print "wav_file_size = ",wav_file_size


file_split_size = 10000000  # 10Mb OR 10, 000, 000 bytes
total_chunks =  wav_file_size // file_split_size

#Get chunk size by following method #There are more than one ofcourse
#for  duration_in_sec (X) -->  wav_file_size (Y)
#So   whats duration in sec  (K) --> for file size of 10Mb
#  K = X * 10Mb / Y

chunk_length_in_sec = math.ceil((duration_in_sec * 10000000 ) /wav_file_size)   #in sec
chunk_length_ms = chunk_length_in_sec * 1000
chunks = make_chunks(myaudio, chunk_length_ms)

#Export all of the individual chunks as wav files

for i, chunk in enumerate(chunks):
    chunk_name = "chunk{0}.wav".format(i)
    print "exporting", chunk_name
    chunk.export(chunk_name, format="wav")
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输出:

Python 2.7.9 (default, Dec 10 2014, 12:24:55) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> ================================ RESTART ================================
>>> 
sample_width= 2
channel_count= 2
duration_in_sec= 589
frame_rate= 44100
wav_file_size =  103899600
exporting chunk0.wav
exporting chunk1.wav
exporting chunk2.wav
exporting chunk3.wav
exporting chunk4.wav
exporting chunk5.wav
exporting chunk6.wav
exporting chunk7.wav
exporting chunk8.wav
exporting chunk9.wav
exporting chunk10.wav
>>> 
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