Sör*_*ren 7 python matplotlib seaborn
我用seaborn.heatmap()渲染了一个热图。但是,出于某种目的,我需要在情节周围使用框架。
matplotlib.rcParams['axes.edgecolor'] = 'black'
matplotlib.rcParams['axes.linewidth'] = 1
两者都不起作用。
小智 8
sns.heatmap(数据集, linewidths=1, linecolor='black')
ax = sns.heatmap(x)
for _, spine in ax.spines.items():
spine.set_visible(True)
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不知道是否有技术命令,但如果您想模仿这种行为,请尝试使用axhlineand axvline:
import string
import numpy as np
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
letters = string.ascii_letters
rs = np.random.RandomState(33)
d = pd.DataFrame(data=rs.normal(size=(100, 26)),
columns=list(letters[:26]))
# Compute the correlation matrix
corr = d.corr()
# Generate a mask for the upper triangle
mask = np.zeros_like(corr, dtype=np.bool)
mask[np.triu_indices_from(mask)] = True
# Set up the matplotlib figure
f, ax = plt.subplots(figsize=(11, 9))
# Generate a custom diverging colormap
cmap = sns.diverging_palette(220, 10, as_cmap=True)
# Draw the heatmap with the mask and correct aspect ratio
ax = sns.heatmap(corr, mask=mask, cmap=cmap, vmax=.3,
square=True, xticklabels=5, yticklabels=5,
linewidths=.5, cbar_kws={"shrink": .5}, ax=ax)
ax.axhline(y=0, color='k',linewidth=10)
ax.axhline(y=corr.shape[1], color='k',linewidth=10)
ax.axvline(x=0, color='k',linewidth=10)
ax.axvline(x=corr.shape[0], color='k',linewidth=10)
plt.show()
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,这导致:
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