单击按钮后如何显示NSMenu我的旁边NSButton.
这就是我到目前为止所拥有的.
@IBOutlet weak var BtnMenu: NSButton!
// Menu
let appMenu = NSMenu()
let showPrefsMenuItem = NSMenuItem(title: "Preferences...", action: #selector(VC.showPrefs(_:)), keyEquivalent: "")
let showAboutMenuItem = NSMenuItem(title: "About", action: #selector(VC.showAbout(_:)), keyEquivalent: "")
let quitAppMenuItem = NSMenuItem(title: "Quit", action: #selector(VC.quitApp(_:)), keyEquivalent: "")
override func viewDidLoad() {
super.viewDidLoad()
// Set up menu
self.appMenu.addItem(self.showPrefsMenuItem)
self.appMenu.addItem(self.showAboutMenuItem)
self.appMenu.addItem(NSMenuItem.separatorItem())
self.appMenu.addItem(self.quitAppMenuItem)
}
// Shows the app menu
@IBAction func openMenu(sender: NSButton) {
self.appMenu.popUpMenuPositioningItem(self.appMenu.itemAtIndex(0), atLocation: NSEvent.mouseLocation(), inView: nil)
}
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但是现在,菜单显示在鼠标位置.Theresa是一种显示按钮旁边菜单的方法吗?
谢谢.
这就是我解决它的方式:
let p = NSPoint(x: sender.frame.origin.x, y: sender.frame.origin.y - (sender.frame.height / 2))
self.appMenu.popUp(positioning: nil, at: p, in: sender.superview)
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在这种情况下,菜单显示在单击的按钮下.
小智 6
斯威夫特3.
在按钮下显示NSMenu:
let p = NSPoint(x: 0, y: sender.frame.height)
appMenu.popUp(positioning: nil, at: p, in: sender)
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在按钮上显示NSMenu:
let p = NSPoint(x: sender.frame.width, y: 0)
appMenu.popUp(positioning: nil, at: p, in: sender)
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